Answer:
1782 cm³
Step-by-step explanation:
First, you measure the volume of the cuboid as a whole which is length x breadth x height, 9 x 12 x 18 = 1944 cm³. Then measure the volume occupied by the space, 3 x 3 x 18 since the hole runs along the entire length = 162 cm³.
Then you subtract the volume occupied by the hole from the volume of the cuboid in total, 1944 - 162 = 1782 cm³
The solution to the problem is as follows:
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the genaral term is 5Cr(-1)^r 2^r x^(5-2r)
and so need 5-2r = -1 => r = 3
Coeff is then 5C3 (-1)^3 2^3 = -80
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-7/9 is repeating
42/50 is terminating
-1/125 is terminating
-77/600 is repeating
179/200 is terminating
5/11 is terminating
The way to figure this out is just by dividing the Numerator (top number) by the denomiter (bottom number)
Example 5÷11=.45454545 repeating
Answer:
1.1
Step-by-step explanation:
In this image, we can see that every box, we add 0.2
From 0.1 to 0.3, we add 0.2
We continue with this pattern for the rest of the boxes
When adding decimals, you can imagine it like you are adding normal numbers, and that you are carrying extra (more than 9) to the next column in the same way.
{column/place value}
At first, it might seem like adding 0.2 to 0.9 would result in 0.11, but let's think that through a little bit more. We know that 0.1 is less than 0.2, so, it doesn't make sense for that to be the sum.
Instead, we have to carry the 11 over to the other side of the decimal. (This is because each place value is equal to 10 of the value to the right. If we add digits in the ones place that add up to 10, we carry the "1" over to the right, into the tens place.)
So, we carry the "1" from 11 to the one's place. Now, we are left with
1.1
(hope this helps!! decimals can be tricky at first)