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Dafna1 [17]
3 years ago
14

There are exactly 2.54 centimeters in 1 inch. When using this conversion factor, how many significant figures are you limited t

Mathematics
1 answer:
IgorC [24]3 years ago
5 0

Significant figures tells us that about how may digits we can count on to be precise given the uncertainty in our calculations or data measurements.

Since, one inch  = 2.54 cm.

This is equivalent as saying that 1.0000000.. inch = 2.540000... cm.

Since the inch to cm conversion doesn't add any uncertainty, so we are free to keep any and all the significant figures.

Since, being an exact number, it has an unlimited number of significant figures and thus when we convert inch to cm we multiply two exact quantities together. Therefore, it will have infinite number of significant figures.

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Oliva ties 2.5 feet of ribbon on to 1 balloon how many yards of ribbon dose olivia need for 18 balloons
Bezzdna [24]

Olivia needs 15 yards of ribbon.

2.5x18=45 feet

divide 45ft by 3 to see how many yards that would be.

45/3=15

Hope that I helped

4 0
3 years ago
The price is three for $1.48 how much will one pepper cost?
mr Goodwill [35]

Answer:

$0.4933

Step-by-step explanation:

i guess

Just divided by 3 ;)

8 0
2 years ago
3. Let A, B, C be sets and let ????: ???? → ???? and ????: ???? → ????be two functions. Prove or find a counterexample to each o
Fiesta28 [93]

Answer / Explanation

The question is incomplete. It can be found in search engines. However, kindly find the complete question below.

Question

(1) Give an example of functions f : A −→ B and g : B −→ C such that g ◦ f is injective but g is not  injective.

(2) Suppose that f : A −→ B and g : B −→ C are functions and that g ◦ f is surjective. Is it true  that f must be surjective? Is it true that g must be surjective? Justify your answers with either a  counterexample or a proof

Answer

(1) There are lots of correct answers. You can set A = {1}, B = {2, 3} and C = {4}. Then define f : A −→ B by f(1) = 2 and g : B −→ C by g(2) = 4 and g(3) = 4. Then g is not  injective (since both 2, 3 7→ 4) but g ◦ f is injective.  Here’s another correct answer using more familiar functions.

Let f : R≥0 −→ R be given by f(x) = √

x. Let g : R −→ R be given by g(x) = x , 2  . Then g is not  injective (since g(1) = g(−1)) but g ◦ f : R≥0 −→ R is injective since it sends x 7→ x.

NOTE: Lots of groups did some variant of the second example. I took off points if they didn’t  specify the domain and codomain though. Note that the codomain of f must equal the domain of

g for g ◦ f to make sense.

(2) Answer

Solution: There are two questions in this problem.

Must f be surjective? The answer is no. Indeed, let A = {1}, B = {2, 3} and C = {4}.  Then define f : A −→ B by f(1) = 2 and g : B −→ C by g(2) = 4 and g(3) = 4. We see that  g ◦ f : {1} −→ {4} is surjective (since 1 7→ 4) but f is certainly not surjective.  Must g be surjective? The answer is yes, here’s the proof. Suppose that c ∈ C is arbitrary (we  must find b ∈ B so that g(b) = c, at which point we will be done). Since g ◦ f is surjective, for the  c we have already fixed, there exists some a ∈ A such that c = (g ◦ f)(a) = g(f(a)). Let b := f(a).

Then g(b) = g(f(a)) = c and we have found our desired b.  Remark: It is good to compare the answer to this problem to the answer to the two problems

on the previous page.  The part of this problem most groups had the most issue with was the second. Everyone should  be comfortable with carefully proving a function is surjective by the time we get to the midterm.

3 0
3 years ago
What is the value of s in the equation 3r = 10 + 5s, when r = 10?
kupik [55]
S = 4

3(10) = 10 + 5s
30 = 10 + 5s
30 - 10 = 5s
20 = 5s
20 ÷ 5 = s
4 = s
4 0
3 years ago
Read 2 more answers
Hello, I have a science project and I need to write an essay about a NON FAMOUS scientist any suggestions?
Mrrafil [7]
Use google and get some ideas. Also look up some non famous scientists and get some info about them
6 0
3 years ago
Read 2 more answers
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