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3 years ago

There are exactly 2.54 centimeters in 1 inch. When using this conversion factor, how many significant figures are you limited t

1 answer:

5 0

Significant figures tells us that about how may digits we can count on to be precise given the uncertainty in our calculations or data measurements.

Since, one inch = 2.54 cm.

This is equivalent as saying that 1.0000000.. inch = 2.540000... cm.

Since the inch to cm conversion doesn't add any uncertainty, so we are free to keep any and all the significant figures.

Since, being an exact number, it has an unlimited number of significant figures and thus when we convert inch to cm we multiply two exact quantities together. Therefore, it will have infinite number of significant figures.

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3 years ago

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To divide by a number with a decimal point, the decimal point to the right place.

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4 years ago

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Claire has a hot tub with a diameter of 7 feet. She wants to purchase a cover to protect the hot tub. What is the area of the co

lara [203]

She needs to purchase a cover to protect the hot tub of an area of 38.5 square feet.

<h3>What is a circle?</h3>

It is a locus of a point drawn at an equidistant from the center. The distance from the center to the circumference is called the radius of the circle.

Claire has a hot tub with a diameter of 7 feet. She wants to purchase a cover to protect the hot tub.

The area of the circle is given by

$\rm Area = \dfrac{\pi}{4}d^2$

We have d = 7 ft, then the area of the circle will be

$\rm Area = \dfrac{3.14}{4}*7^2\\\\Area = 38.5 \ ft^2$

More about the circle link is given below.

brainly.com/question/11833983

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2 years ago

Answer please due today

mezya [45]

Answer:

CD=9

Step-by-step explanation:

ΔABD=>

AD²=AB² + BD² [Pythagorean Theorem]

BD²= AD²-AB²

BD²=9²-3²

BD²=72

BD=√72=6√2....(1)

ΔBCD=>

CD²=BD²+BC²

CD²=(6√2)² + 3²

CD²=72+9

CD²=81

CD=√81

CD=9

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3 years ago

A particular variety of watermelon weighs on average 22.4 pounds with a standard deviation of 1.36 pounds. Consider the sample m

daser333 [38]

Answer:

a) 22.4 pounds.

b) 0.17 pounds.

c) 0.0127 = 1.27% approximate probability the sample mean weight will be less than 22.02.

d) c = 22.62

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .