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3 years ago

Choose the three decimals that make the equation true 68.05 68.12 680.2 68.006 68.3 68.049 68.1

Mathematics

1 answer:

Alex_Xolod [135]3 years ago

6 0

It can be noted that the <em>decimals</em> that fit into the equation will be 68.05, 68.3, and 68.006.

<h3>How to calculate the equation</h3>

Your information is incomplete as the original equation isn't given. Therefore, an overview will be given.

Let's assume that the statement is that you should find three decimals where the addition equals 204.086

In this case, you've to look at the decimals and add the three that will give the number above. In this case, the three decimals will be:

68.05 + 68.3 + 68.006

= 204.086

Learn more about equations on:

brainly.com/question/13763238

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The ratio of an angle to its supplement is 3:5. Find the angle and it's supplement.

schepotkina [342]

Givens

Call one of the angles = x

The other one is 180 - x

They are in the ratio of 3 to 5

Equation

3/5 = x / (180 - x)

Solve

3/5 = x / (180 - x) Cross Multiply

3*(180 - x) = 5x

540 - 3x = 5x Add 3x to both sixes

540 = 5x + 3x

540 = 8x

Divide both sides by 8

540 / 8 = x

x = 67.5

One angle is 67.5

The supplement is 180 - 67.5 = 112.5

Check

67.5/112.5 = 0.6 which is the same thing as 3/5

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4 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

im so sad i literally cried for 10 min straight because i have three 70's on my grade progress report and my mom only wants 80's

givi [52]

Answer:

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3 years ago

Factor of 4-(2a+3b)^2

Anna71 [15]

$4-(2a+3b)^2$

$(2a+3b)^2 :$

$4a^2+12ab+9b^2$

$= 4-(4a^3+12ab+9b^2)$

$=-(4a^2)-(12ab)-(9b^2)$

apply minus - plus rules :

$+(-a)=-a$

Refine:

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<span>hope this helps!</span>

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3 years ago

Find the solution to the system of equations given below using elimination by addition.

mixer [17]

Answer:

x = 7 , y = -1

Step-by-step explanation by elimination:

Solve the following system:

{10 x + 10 y = 60 | (equation 1)

5 x - 5 y = 40 | (equation 2)

Subtract 1/2 × (equation 1) from equation 2:

{10 x + 10 y = 60 | (equation 1)

0 x - 10 y = 10 | (equation 2)

Divide equation 1 by 10:

{x + y = 6 | (equation 1)

0 x - 10 y = 10 | (equation 2)

Divide equation 2 by 10:

{x + y = 6 | (equation 1)

0 x - y = 1 | (equation 2)

Multiply equation 2 by -1:

{x + y = 6 | (equation 1)

0 x+y = -1 | (equation 2)

Subtract equation 2 from equation 1:

{x+0 y = 7 | (equation 1)

0 x+y = -1 | (equation 2)

Collect results:

Answer: {x = 7 , y = -1

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4 years ago