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adell [148]
3 years ago
6

A pyramid with a square base has a volume of 600cm^3 and the length of the bas is 10 cm. What is the height of the pyramid?

Mathematics
1 answer:
Artyom0805 [142]3 years ago
4 0

Answer:

h=3

Solving forh

h=3V

lw=3·600

10·60=3

Step-by-step explanation:

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Let​ T: set of real numbers R Superscript nℝnright arrow→set of real numbers R Superscript mℝm be a linear​ transformation, and
Klio2033 [76]

Answer:

\{T(v_1), T(v_2), T(v_3)\} is linearly dependent set.

Step-by-step explanation:

Given:  \{v_1,v_2,v_3\} is a linearly dependent set in set of real numbers R

To show: the set \{T(v_1), T(v_2), T(v_3)\} is linearly dependent.

Solution:

If \{v_1,v_2,v_3,...,v_n\} is a set of linearly dependent vectors then there exists atleast one k_i:i=1,2,3,...,n such that k_1v_1+k_2v_2+k_3v_3+...+k_nv_n=0

Consider k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0

A linear transformation T: U→V satisfies the following properties:

1. T(u_1+u_2)=T(u_1)+T(u_2)

2. T(au)=aT(u)

Here, u,u_1,u_2∈ U

As T is a linear transformation,

k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0\\T(k_1v_1)+T(k_2v_2)+T(k_3v_3)=0\\T(k_1v_1+k_2v_2+k_3v_3)=0\\

As \{v_1,v_2,v_3\} is a linearly dependent set,

k_1v_1+k_2v_2+k_3v_3=0 for some k_i\neq 0:i=1,2,3

So, for some k_i\neq 0:i=1,2,3

k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0

Therefore, set \{T(v_1), T(v_2), T(v_3)\} is linearly dependent.

6 0
3 years ago
BRAINLIEST ON THE LINE INFO IN PHOTO BELOW
victus00 [196]

Answer:

32 days is my final answer

Step-by-step explanation:

6 0
3 years ago
PLEASE HELP!!!!
KIM [24]
1. 3rd one

2. f(x) = 7x - 5
    f(2) = 7(2) - 5
    f(2) = 14 - 5
    f(2) = 9

3. c(n) = 0.75n - 0.25

4. (0,0)(2,4)
    slope = (4 - 0) / (2 - 0) = 4/2 = 2
    answer is : y = 2x

7 0
3 years ago
Read 2 more answers
How might this number be shown on a calculator?<br> 5.31x1037 (37 is above 10)<br> [?]e[ ]
Arisa [49]

Answer:

5.31E37

Step-by-step explanation:

Given

5.31 * 10^{37}

Required

How it'd be displayed on a calculator

Standard calculators, today are built to always convert huge numbers or extremely small number to scientific notations;

This was done to allow the calculator fit each values on its screen

5.31 * 10^{37} is such a big number that it'll require the calculator to display it using scientific notations;

So, basically we have to convert 5.31 * 10^{37} to scientific notaton;

This is achieved by replacing *10^{37} with E37

So, 5.31 * 10^{37} is equivalent to 5.31E37

6 0
3 years ago
How to find the square root of 56 without using a calculator
Olegator [25]
There an old algorythmic method similar to long division:-
          
                 7 .   4   8   3
              -----------------
              ) 56. 00 00 00
          7  ) 49
              ) ---
     144   )   7 00
             )    576   
                  ----
  148 8 )     12400
           )      11904
                  -------
          )       496 00
1496 3  )    44889    

THis gives the square root as 7.48  to the nearest hundredth

 
7 0
3 years ago
Read 2 more answers
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