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brilliants [131]
2 years ago
8

Fill in the blanks to solve this equation (ANSWER QUICK)

Mathematics
1 answer:
SVETLANKA909090 [29]2 years ago
3 0

Answer:

Step-by-step explanation:

5+\frac{1}{2} (14b-8)=-6

5+7b-4=-6

7b+1=-6

   -1      -1

7b=-7

/7      /7

b=-1

Answers in order:

7 + 7b - 4 = -6

7b + 1 = -6

7b = -7

b = -1

Hope this helps!

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I think C would be 3.25

Step-by-step explanation:

Because if you divide 65/20+3.25 sorry if i'm wrong.

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You can helps me? <br>f(x) = x + 20 <br>g(x) = x + 5 <br>(f o g) (2) = ?​
pav-90 [236]
<h2>♪Answer : </h2>
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»(f o g)(2)

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2 years ago
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This is a question on my partial fractions homework, but no matter what I try I can't figure it out..
Ierofanga [76]
\dfrac{x^2+x+1}{(x+1)^2(x+2)}=\dfrac{a_1x+a_0}{(x+1)^2}+\dfrac b{x+2}
\implies\dfrac{x^2+x+1}{(x+1)^2(x+2)}=\dfrac{(a_1x+a_0)(x+2)+b(x+1)^2}{(x+1)^2(x+2)}
\implies x^2+x+1=(a_1+b)x^2+(2a_1+a_0+2b)x+(2a_0+b)
\implies\begin{cases}a_1+b=1\\2a_1+a_0+2b=1\\2a_0+b=1\end{cases}\implies a_1=-2,a_0=-1,b=3

So you have

\displaystyle\int_0^2\frac{x^2+x+1}{(x+1)^2(x+2)}\,\mathrm dx=-2\int_0^2\frac x{(x+1)^2}\,\mathrm dx-\int_0^2\frac{\mathrm dx}{(x+1)^2}+3\int_0^2\frac{\mathrm dx}{x+2}
=\displaystyle-2\int_1^3\dfrac{x-1}{x^2}\,\mathrm dx-\int_0^2\frac{\mathrm dx}{(x+1)^2}+3\int_0^2\frac{\mathrm dx}{x+2}

where in the first integral we substitute x\mapsto x+1.

=\displaystyle-2\int_1^3\left(\frac1x-\frac1{x^2}\right)\,\mathrm dx-\frac1{1+x}\bigg|_{x=0}^{x=2}+3\ln|x+2|\bigg|_{x=0}^{x=2}
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=-2\left(\ln3+\dfrac13-1\right)-\dfrac23+3\ln2
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4 0
3 years ago
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