Ask question

Ask question

All categories

3 years ago

6

Two cars leave a town at the same time heading in opposite directions. One car is traveling 12 mph faster than the other. After

2 hours, they are 232 miles apart. What is the speed of each car?

1 answer:

Katena32 [7]3 years ago

4 0

<span>Find the speed of each car.
Let a be the first car
Let b be the second car
=> a = x miles per hour
=> b = x + 12 miles per hour
=> 2 (x+ x + 12) = 232 miles per hour
=> 2x + 12 = 232
=> 2x + 12 = 116
=> 2x = 116 - 12
=> 2x / 2 = 104 / 2
=> x = 52 (speed of Car A)
=> 52 + 12 = 64 miles per hour (speed of Car B)</span>

You might be interested in

Number 15. Find the equation of the line that passes through (3,-1) and is perpendicular to the line that passes through (-5, 2)

MArishka [77]

For lines to be perpendicular their slopes must be negative reciprocals of one another, mathematically:

m1*m2=-1

So we first need to find the slope of the reference line.

m=(y2-y1)/(x2-x1)=(7-2)/(-1--5)=5/4

So the perpendicular line will have a slope of:

5m/4=-1

m=-4/5

So our perpendicular line so far is:

y=-4x/5+b, now we can use point (3,-1) to solve for the y-intercept, "b"

-1=-4(3)/5+b

-1=-12/5+b

-5/5+12/5=b

7/5=b

So the line is:

y=-4x/5+7/5 or more neatly

y=(-4x+7)/5

y=-0.8x+1.4

3 0

3 years ago

URGENT!!!!!!! HELP PLEASE!!!!!!

IRISSAK [1]

Answer:

$x^\frac{2}{3}$

Step-by-step explanation:

Using the power of power rule (multiply the exponents)

$x^\frac{4}{3}$ × $^\frac{1}{3}$ $x^\frac{2}{3}$ × $^\frac{1}{3}$

$x^\frac{4}{9}$ $x^\frac{2}{9}$

When exponents are multiplied, add the answers:

x ^ ( 4/9 + 2/9 )

x ^ ( 6/9 )

x ^ ( 2/3 )

6 0

3 years ago

Question 1 (Multiple Choice Worth 5 points)

AysviL [449]

Answer:

Answer should be I 16-(-10) I = 26

But I guess it's the last choice you listed, I -10-16 I = 26

6 0

3 years ago

Use the table to interpret the axes labels of the

yKpoI14uk [10]

Answer:

Texting speed

Step-by-step explanation:

7 0

4 years ago

Read 2 more answers

Write the frost ten terms of a sequence whose first term is -10 and whose common difference is -2

Temka [501]

Answer:

$-10,-12,-14,-16,-18,-20,-22,-24,-26,-28,...$

Step-by-step explanation:

we know that

In an <u><em>Arithmetic Sequence</em></u> the difference between one term and the next is a constant, called the common difference

The formula for an Arithmetic Sequence is equal to

$a_n=a_1+(n-1)d$

where

d is the common difference

n is the number of terms

a_1 is the first term of the sequence

In this problem we have

$a_1=-10\\d=-2$

substitute

$a_n=-10+(n-1)(-2)$

$a_n=-10-2n+2$

$a_n=-2n-8$

so

<u><em>Find the first ten terms</em></u>

$a_1=-10$

For n=2 ----> $a_2=-2(2)-8=-12$

For n=3 ----> $a_3=-2(3)-8=-14$

For n=4 ----> $a_4=-2(4)-8=-16$

For n=5 ----> $a_5=-2(5)-8=-18$

For n=6 ----> $a_6=-2(6)-8=-20$

For n=7 ----> $a_7=-2(7)-8=-22$

For n=8 ----> $a_8=-2(8)-8=-24$

For n=9 ----> $a_9=-2(9)-8=-26$

For n=10 ----> $a_1_0=-2(10)-8=-28$

The sequence is

$-10,-12,-14,-16,-18,-20,-22,-24,-26,-28,...$

5 0

3 years ago