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3 years ago

60PTS Chef Alfredo invested $4800 at a simple interest rate of 5% and can now afford a $6,000

Mathematics

1 answer:

garik1379 [7]3 years ago

7 0

Answer:

An oft-repeated water vapor myth is that warm air can “hold” more water vapor than cool air because as the air warms its molecules move farther apart, making room for more molecules.

Step-by-step explanation:

You might be interested in

Find the area of the shaded region.

Papessa [141]

Answer:

21.46 cm²

Step-by-step explanation:

because the question want only for the SHADED REGION but NOT AREA OF THE SQUARE

(if we just multiply 10x10. you will get the area of a square which is hundered)

To find the shaded region:

1. area of a circle is πr² (we have 4 circle there)

2. Find the area of all circle

# how do we know the radius?

- half of 10 is 5

- 5 is the diameter of each circle

- the radius is half of 5 which is 2.5

- π(2.5)² = 25/4π (area of 1 circle)

3. since we have 4 circle then, 25/4π x 4 = 25π

4. the area of the square is 100cm²

5. we want the shaded region so we have to minus the area of the circle

6. 100 - 25π (use your calculator to find the answer)

answer should be 21.46 cm²

(hope this helps)

8 0

4 years ago

Find the area of the trapezoid.

goldenfox [79]

Answer:

Step-by-step explanation:

AREA=

$\frac{(a + b)}{2} \times h$

$\frac{15 + 6}{2} \times 10$

=105m²

6 0

3 years ago

According to Lambert's law, the intensity of light from a single source on a flat surface at point P is given by Upper L equal

malfutka [58]

Answer:

(a) $L = k*(1 - sin^{2}(\theta))$

(b) L reaches its maximum value when θ = 0 because cos²(0) = 1

Step-by-step explanation:

Lambert's Law is given by:

$L = k*cos^{2}(\theta)$ (1)

(a) We can rewrite the above equation in terms of sine function using the following trigonometric identity:

$cos^{2}(\theta) + sin^{2}(\theta) = 1$

$cos^{2}(\theta) = 1 - sin^{2}(\theta)$ (2)

By entering equation (2) into equation (1) we have the equation in terms of the sine function:

$L = k*(1 - sin^{2}(\theta))$

(b) When θ = 0, we have:

$L = k*cos^{2}(\theta) = k*cos^{2}(0) = k$

We know that cos(θ) is a trigonometric function, between 1 and -1 and reaches its maximun values at nπ, when n = 0,1,2,3...

Hence, L reaches its maximum value when θ = 0 because cos²(0) = 1.

I hope it helps you!

5 0

3 years ago

Read 2 more answers

Hello! Happy Tuesday! I have a math test today in 30 min and i'm studying. I know I will fail but I will try. I am really nervou

Yuri [45]

U just need to believe in your self and don’t give up even if the questions are hard. Ask for help always even during test the teacher might give u hints. Take your mind of it for about five min to give ur brain a break if your getting overwhelmed. Hope this helps. U got this!!!

4 0

3 years ago

Dos cuadrados de lado

Kaylis [27]

La franja amarilla del rectángulo tiene un área de 30 centímetros cuadrados.

<h3>¿Cuál es el área de la franja amarilla del rectángulo?</h3>

En este problema tenemos un rectángulo formado por dos cuadrados que se traslapan uno al otro. La franja amarilla es el área en la que los cuadrados se traslapan. La anchura del rectángulo es descrita por la siguiente ecuación:

(10 - x) + 2 · x = 17

Donde x se mide en centímetros.

A continuación, despejamos x en la ecuación descrita:

10 + x = 17

x = 7

Ahora, el área de la franja amarilla se determina mediante la fórmula de area de un rectángulo:

A = b · h

Donde:

b - Base del rectángulo, en centímetros.
h - Altura del rectángulo, en centímetros.
A - Área del rectángulo, en centímetros cuadrados.

A = (10 - 7) · 10

A = 3 · 10

A = 30

El área de la franja amarilla del rectángulo es igual a 30 centímetros cuadrados.

Para aprender más sobre áreas de rectángulos: brainly.com/question/23058403

#SPJ1

8 0

1 year ago