The <em>polynomial-like</em> expression is satisfied by the <em>real</em> value <em>x = 1</em>.
<h3>How to determine the real solution of a polynomial-like expression</h3>
In this question we must apply the concepts of logarithms and <em>algebra</em> properties to solve the <em>entire</em> expression. Initially, we expand the right part of the expression:
![(2^{x}-4)^{3} + (4^{x}-2)^{3} = [(2^{x}-4)+(4^{x}-2)]^{3}](https://tex.z-dn.net/?f=%282%5E%7Bx%7D-4%29%5E%7B3%7D%20%2B%20%284%5E%7Bx%7D-2%29%5E%7B3%7D%20%3D%20%5B%282%5E%7Bx%7D-4%29%2B%284%5E%7Bx%7D-2%29%5D%5E%7B3%7D)
Hence, the roots of the pseudopolynomial are 
and 
. Only the second one have a real value of <em>x</em>. Hence, we have the following solution:
The <em>polynomial-like</em> expression is satisfied by the <em>real</em> value <em>x = 1</em>. 
To learn more on logarithms, we kindly invite to check this verified question: brainly.com/question/24211708
Answer:
7.9.
Step-by-step explanation:
Use the Pythagorean Theorem.
√((-5)^2 + (6)^2 + (-1)^2) = √62 = 7.87 = 7.9.
You can use many different strategies to find the answer to a division
problem. One strategy is to use repeated subtraction. To find 123 ÷ 36,
think: How many groups of 36 are there in 123? Start with 123. Subtract
36 repeatedly. Count how many times you subtracted: 123 − 36 = 87 (1); 87 − 36 = 51 (2); 51 − 36 = 15 (3); 15 < 36. There are 3 groups of 36 in 123 with 15 left over. Therefore, 123 ÷ 36 = 3 R15.
Answer:
Radius of the circle = 119
Step-by-step explanation:
here's the solution :-
we know that the perpendicular from centre to any chord bisects the chord so,
=》AT = 1/2 × OT
=》AT = 1/2 × 210
=》AT = 105
now, join VT ( by construction )
so, triangle VTA is a right angled triangle, with right angle on A.
now, by pythagorous theorem,
=》VT^2 = VA^2 + AT^2
=》VT^2 = (56)^2 + (105)^2
=》VT^2 = 3136 + 11025
=》VT =
=》VT = 119
and VT joins the centre of the circle with the circumference, hence VT is the radius of the circle .
