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kenny6666 [7]
2 years ago
15

What is the maximum or minimum value? f(x) = -(x - 8) ^ 2 - 25

Mathematics
1 answer:
Rina8888 [55]2 years ago
8 0

Answer:

You have a maximum when the parabola opens down (-x^2), and a minimum when it opens up (+x^2). In your case, it opens down because of the -. That is the special notation, the vertex of the parabola is already there.

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the lateral area of a cone is 574 pi cm2. The radius is 19.6 cm. What is the slant height to the nearest tenth of a centimeter?
bulgar [2K]
\bf \textit{lateral area of a cone}\\\\
LA=\pi r\sqrt{r^2+h^2}~~
\begin{cases}
r=radius\\
\sqrt{r^2+h^2}=slant~height\\
-----------\\
LA=574\pi \\
r=19.6
\end{cases}
\\\\\\
574\pi =\pi (19.6)\sqrt{r^2+h^2}\implies \cfrac{574\pi }{19.6\pi }=\sqrt{r^2+h^2}
\\\\\\
\cfrac{574}{19.6}=\sqrt{r^2+h^2}
5 0
3 years ago
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9966 [12]

Answer:

150°

Step-by-step explanation:

It is given that CosФ < 0 i.e CosФ is negative.

Therefore, the minimum the value of Ф for which CosФ <0 will be in the second quadrant i.e 90° < Ф < 180°.

Now it is also given that, Sin Ф =0.5 {the value of SinФ is positive because Sin value is positive in second quadrant.}

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