Answer:
Yes
Step-by-step explanation:
The sum must be greater than 8 it can't be 7 anyway. Sums can be 9, 10 or 12. P = (4+3+1)/36 = 3/36
Answer:
Step-by-step explanation:
Answer:
<h3>X<5 and X<3</h3>
Step-by-step explanation:
To solve this problem, first, you have to isolate it on one side of the equation. Remember to solve this problem, isolate x on one side of the equation.
x+3<8 and 3(x+4)-11<10
x+3<8
x+3-3<8-3 (First, subtract 3 from both sides.)
8-3 (Solve.)
8-3=5
x<5
3(x+4)-11<10
3(x+4)-11+11<10+11 (Add 11 from both sides.)
10+11 (Solve.)
10+11=21
3(x+4)<21
3(x+4)/3<21/3 (Next, divide by 3 from both sides.)
21/3 (Solve.)
21/3=7
x+4<7
x+4-4<7-4 (Then, subtract 4 from both sides.)
7-4=3
x<3
The correct answer is x<5 and x<3.
Y=mx+b
3= -1/2(6) + b
3= -3+b
3+3= b
b= 6
y= mx+b
2= -1/2x+ 6
2-6 = -1/2x
-4 = -1/2x
-4•-2 = -1/2x •-2
x = 8
(8,2)
Answer:
True
Step-by-step explanation:
In order to calculate this, we simply need to replace the variable c with the value of -8 and solve the inequality.
-9c >= 63
-9 * -8 >= 63
72 >= 63
Since both values are negative the product will be positive. This product is 72 which is in fact greater than 63, thus making the statement True
