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Vlad1618 [11]
2 years ago
8

Evaluate ∫3x2sin(x3)cos(x3)dx by

Mathematics
1 answer:
liraira [26]2 years ago
6 0

Answer:

Evaluate ∫3x2sin(x3)cos(x3)dx

Step-by-step explanation:

hello        (a) using the substitution u=sin(x3)  because

du =3x²(cos x3)dx

you have   ∫3x2sin(x3)cos(x3)dx = ∫udu=u²/2 +c............continu

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Step-by-step explanation:

Given the endpoints of the diameter of the circle, we  need to find the midpoint, which is the center of the circle.

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3 years ago
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krok68 [10]
D. X and y values written in the form of (x,y)
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3 years ago
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Can you work out G and H for me please. preferably telling me how you did it aswell
Veronika [31]
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and to calculate h we need to use the sine rule
\frac{h}{ \sin(22) }  =  \frac{g}{ \sin(32) }  \\  \frac{h}{ \sin(22) }  =  \frac{17.03}{ \sin(32) }  \\ h =  \frac{17.03}{ \sin(32) } \times  \sin(22)   \\ h = 12.04cm
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3 years ago
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