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2 years ago

Evaluate ∫3x2sin(x3)cos(x3)dx by

Mathematics

1 answer:

liraira [26]2 years ago

6 0

Answer:

Evaluate ∫3x2sin(x3)cos(x3)dx

Step-by-step explanation:

hello (a) using the substitution u=sin(x3) because

du =3x²(cos x3)dx

you have ∫3x2sin(x3)cos(x3)dx = ∫udu=u²/2 +c............continu

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Step-by-step explanation:

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3 years ago

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Can you work out G and H for me please. preferably telling me how you did it aswell

Veronika [31]

Abd is a right angled triangle so by pythagoras we know
${g}^{2} = {11}^{2} + {13}^{2} \\ {g}^{2} = 290 \\ g = \sqrt{290} \: or \: g = 17.03cm$
and to calculate h we need to use the sine rule
$\frac{h}{ \sin(22) } = \frac{g}{ \sin(32) } \\ \frac{h}{ \sin(22) } = \frac{17.03}{ \sin(32) } \\ h = \frac{17.03}{ \sin(32) } \times \sin(22) \\ h = 12.04cm$
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