I need help on this exact question: let x = -7 -x + x

A hiker cycles 9 miles in 2/3 of an hour. Make a chart and fill it in to show how far he will bike if he maintains the same pace

Arada [10]

Answer:

2 hours: 27 miles, 3 hours: 40.5 miles, 3.5 hours: 47.25 miles

Step-by-step explanation:

1.) If a hiker hikes 9 miles in 2/3 of an hour, he will hike 4.5 (Half of 2/3 is 1/3 and half of 9 is 4.5) miles in 1/3 of an hour and 13.5 miles per hour. (1/3 times 3 gives us a whole and 4.5 times 3 is 13.5)

2.) 2 hours: 13.5 * 2 = 27 miles

3.) 3 hours: 13.5 * 3 = 40.5 miles

4.) 3.5 hours: 13.5 * 3.5 = 47.25 miles

6 0

3 years ago

Read 2 more answers

Pls help me fast and give me the steps pls 1+7p-40=80

valentinak56 [21]

Answer:

17

Step-by-step explanation:

1+7p-40=80

-39+7p=80 Move constant to the right

7p=80+39 add the numbers

7p=119 divide both sides by 7

4 0

3 years ago

Read 2 more answers

1.Encuentra la ecuación de la circunferencia que tiene como ecuación ordinaria (x-4)² + (y+5)²= 25 2- encuentra la ecuación gene

rodikova [14]

Responder:

1) x² + y²-8x + 10y + 16 = 0

2) x² + y² + x + 18y + 33 = 0

Explicación paso a paso:

A partir de la pregunta, debemos expresar la ecuación en la forma estándar de un círculo expresado como;

x² + y² + 2gx + 2fy + c = 0 donde;

(-g, -f) es el centro.

1) Para la ecuación (x-4) ² + (y + 5) ² = 25

Expande el paréntesis;

(x-4) ² + (y + 5) ² = 25

x²-8x + 16 + y² + 10x + 25 = 25

x²-8x + 16 + y² + 10y + 25-25 = 0

Recopile términos similares;

x² + y²-8x + 10y + 16 + 0 = 0

x² + y²-8x + 10y + 16 = 0

Por lo tanto, la ecuación requerida es x² + y²-8x + 10y + 16 = 0

2) Para la expresión (x + 1) ² + (y + 9) ² = 49

x² + x + 1 + y² + 18y + 81 = 49

x² + x + 1 + y² + 18y + 81-49 = 0

Recopile términos similares;

x² + y² + x + 18y + 82-49 = 0

x² + y² + x + 18y + 33 = 0

Por tanto, la ecuación requerida es x² + y² + x + 18y + 33 = 0

4 0

2 years ago

Circles and inscribed angles

andreev551 [17]

Answer:

angle formed by two chords in a circle

Step-by-step explanation:

3 0

3 years ago

Does anybody know how to do time with exponential decay

My name is Ann [436]

From the message you sent me:

when you breathe normally, about 12 % of the air of your lungs is replaced with each breath. how much of the original 500 ml remains after 50 breaths

If you think of number of breaths that you take as a time measurement, you can model the amount of air from the first breath you take left in your lungs with the recursive function

$b_n=0.12\times b_{n-1}$

Why does this work? Initially, you start with 500 mL of air that you breathe in, so $b_1=500\text{ mL}$ . After the second breath, you have 12% of the original air left in your lungs, or $b_2=0.12\timesb_1=0.12\times500=60\text{ mL}$ . After the third breath, you have $b_3=0.12\timesb_2=0.12\times60=7.2\text{ mL}$ , and so on.

You can find the amount of original air left in your lungs after $n$ breaths by solving for $b_n$ explicitly. This isn't too hard:

$b_n=0.12b_{n-1}=0.12(0.12b_{n-2})=0.12^2b_{n-2}=0.12(0.12b_{n-3})=0.12^3b_{n-3}=\cdots$

and so on. The pattern is such that you arrive at

$b_n=0.12^{n-1}b_1$

and so the amount of air remaining after $50$ breaths is

$b_{50}=0.12^{50-1}b_1=0.12^{49}\times500\approx3.7918\times10^{-43}$

which is a very small number close to zero.

5 0

3 years ago