Answer:
y = (9/4)x + 2, given that I've assume the correct meaning of "-5x4."
Step-by-step explanation:
A parallel line has the same slope as the reference line,
The reference line is 9x-4y = -5x4, as written. I'm not sure the 4 belongs, but I'll assume it is written correctly. I'm not sure if the term -5x4 is meant to mean -5x^4, -20x or -20. I'll assume -20:
9x-4y = -20
Put the equation into standard slope-intercept form: Y = mx + b, where m is the slope and b is the y-intercept (the value of y when x = 0).
-4y = -9x - 20
y = (9/4)x + 5
This line has a slope of (9/4). The parallel line will have the same slope.
y = (9/4)x + b
We can find a value of b that would shift this line to include (4,7) by using this point in the equation:
y = (9/4)x + b
7 = (9/4)(4) + b
7 = 9 + b
b = 2
The equation of a line parallel to the reference line is y = (9/4)x + 2
