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77julia77 [94]
3 years ago
14

Simplify 3x + 5x + 14x

Mathematics
2 answers:
navik [9.2K]3 years ago
3 0
Simply collect all the like terms together
So..3+5+14 is 22x
Dafna11 [192]3 years ago
3 0
The answer I think is 22x I could be wrong tho
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3 years ago
Bill owed his brother $21.50, but was able to pay him back $18.75. How much does Bill owe his brother now?
Andrew [12]

Answer:

2.75

Step-by-step explanation:

21.50 - 18.75 = $2.75

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2 years ago
A shopkeeper bought a television for Rs. 10000 and he sold it at profit of 25%. What was the selling price of the television? Pl
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3 years ago
2x - 4 &gt; 4<br> ...................
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8 0
3 years ago
Suppose we want to choose 5 colors, without replacement, from 8 distinct colors.1. If the order is relevant, how many can be don
Charra [1.4K]

(1) From the information given, if we want to choose 5 colors from 8 distinct colors and the order in which the selection is made is relevant, then what we have is a permutation.

The formula is given as;

nP_r=\frac{n!}{(n-r)!}

This formula means we need to select/arrange r items out of a total of n items and the anwer derived would be the total number of arrangements possible.

Therefore, we would have;

\begin{gathered} nP_r\Rightarrow_8P_5 \\ _8P_5=\frac{8!}{(8-5)!}\Rightarrow\frac{8!}{3!} \\ _8P_5=\frac{8\times7\times6\times\ldots1}{3\times2\times1}\Rightarrow\frac{40320}{6} \\ _8P_5=6720 \end{gathered}

Therefore, if the order is relevant, this selection can be done in 6,720 ways.

(2) If the order is NOT relevant, then what we need to calculate is a combination and the formula is;

_nC_r=\frac{n!}{(n-r)!r!}

The formula can now be applied as follows;

\begin{gathered} _nC_r\Rightarrow_8C_5 \\ _8C_5=\frac{8!}{(8-5)!\times5!} \\ _8C_5=\frac{8!}{3!\times5!}\Rightarrow\frac{8\times7\times6\times\ldots1}{(3\times2\times1)\times(5\times4\times\ldots1)} \\ _8C_5=\frac{40320}{6\times120} \\ _8C_5=56 \end{gathered}

If the order is not relevant, then the selection can be done in 56 ways.

3 0
1 year ago
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