What is the y-intercept of the function f(x) = –negative StartFraction 2 Over 9 EndFraction. X ?

Mathematics

1 answer:

Mama L [17]2 years ago

3 0

The y-intercept of the given function is 1/3

The given question is looks like incomplete the complete question is ,

What is the y-intercept of the function f(x) = –negative Start Fraction 2 Over 9 End Fraction. x plus Start Fraction 1 Over 3. X?

What is the slope intercept form?

The equation of the line in Slope-Intercept form is

y=mx+C

Where "m" is the slope of the line and "C" is the y-intercept.

Given the function f(x)

$f(x)=\frac{-2}{9} x+\frac{1}{3}$

Since , f(x)=y you can rewrite it

$f(x)=\frac{-2}{9} x+\frac{1}{3}$

Therefore we get,

m=-2/9

and c=1/3

Therefore, the y-intercept of the given function is 1/3

To learn more about the intercept visit:

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3 years ago

I need help finding this answer ASAP

Darya [45]

Answer:

First & Third options

Step-by-step explanation:

$\bigg( {5}^{ \frac{3}{8}} \: . {5}^{ \frac{1}{8}} \bigg)^{3} \\ \\ = \bigg( {5}^{ \frac{3}{8} + \frac{1}{8}} \bigg)^{3} \\ \\ = \bigg( {5}^{ \frac{4}{8}} \bigg)^{3} \\ \\ = \bigg( {5}^{ \frac{1}{2}} \bigg)^{3} \\ \\ = {5}^{ \frac{3}{2}} \\ \\ = \sqrt{ {5}^{3} } \\ \\ \huge\red{ \boxed{\therefore \bigg( {5}^{ \frac{3}{8}} \: . {5}^{ \frac{1}{8}} \bigg)^{3}= \sqrt{ {5}^{3} } }}$