At the start they both have 200?
√4=2, and √45=√(9*5)=√9 *√5=3√5
so you have 2/(3√5)
Multiply both top and bottom by √5 to eliminate the √ in the denominator:
(2√5)/15 is the final answer.
If xy=0
assume that at least x or y=0
3(x-3)=0
therefor
3=0 or x-3=0
3=0 is false
therefor
x-3 mus equal zero
x-3=0
add 3 to both sides
x=3
Answer:
4. H0: u1= u2 Ha; u1≠ u2
5. The smaller value of p supports the null hypothesis.
Step-by-step explanation:
4. The null and alternate hypotheses are
H0: u1= u2 i.e there no difference between the mean pinch strengthof the two surgeries
against the claim
Ha; u1≠ u2 i.e there a difference between the mean pinch strengthof the two surgeries
It can be written like this as well
H0: u1 -u2= 0 i.e there no difference between the mean pinch strengthof the two surgeries
against the claim
Ha; u1 -u2≠ 0 i.e there a difference between the mean pinch strengthof the two surgeries
Part 5. The test having a p- value less than 0.05 tells that the null hypothesis cannot be rejected. Theres no evidence to reject the null hypothesis.
The smaller value of p supports the null hypothesis.
