t N.
In the figure shown below
Answer:
A horizontal line segment M K intersects with line segment J L at their midpoint N.
∠J N M =(5x+2)°
∠ LN M=3( x+ 14)°
So, ∠J N M + ∠ LN M =180°[ These two angles form linear pair.Angles forming linear pair are supplementary.]
⇒5 x+ 2+ 3 (x+ 14) =180 [ By Substitution]
⇒ 5 x+2 +3 x+42°= 180°
⇒ 8 x=180°-44°
⇒8 x= 136°
⇒x= 136°÷8
⇒x=17°
So, ∠J N M =5×17 +2=87°
∠ LN M= 3×(17 +14)=3×31=93
∠J N M =∠K N L [Vertically opposite angles]
∠K N L=87°
The integer would be
positive 5
Let's call the 10 runners A B C D E F G H I J
ABC
ABD
ABE
ABF
ABG
ABH
ABI
ABJ
ACB
ACD
ACE
ACF
ACG
ACH
ACI
ACJ
ADB
ADC
ADE
ADF
ADG
ADH
ADI
ADJ
AEB
AEC
AED
AEF
AEG
AEH
AEI
AEJ
AFB
AFC
AFD
AFE
AFG
AFH
AFI
AFJ
AGB
AGC
AGD
AGE
AGF
AGH
AGI
AGJ
AHB
AHC
AHD
AHE
AHF
AHG
AHI
AHJ
AIB
AIC
AID
AIE
AIF
AIG
AIH
AIJ
AJB
AJC
AJD
AJE
AJF
AJG
AJH
AJI
The above is 60 different ways, but now B C D E F G H I J have to come first, and the proses starts again, until we have covered them all. I'm not going to write them all out but in theory, there is 540 different ways. 9*60=540.
Answer:
The 80% confidence interval for the mean number of words a third grader can read per minute is between 40.4 wpm and 40.8 wpm.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so 
Now, find M as such

In which
is the standard deviation of the population and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 40.6 - 0.2 = 40.4 words per minute.
The upper end of the interval is the sample mean added to M. So it is 40.6 + 0.2 = 40.8 words per minute.
The 80% confidence interval for the mean number of words a third grader can read per minute is between 40.4 wpm and 40.8 wpm.
Answer:
18
Step-by-step explanation: