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3 years ago

For a-b, reduce to the least non-negative residue

Mathematics

1 answer:

Olenka [21]3 years ago

3 0

Answer:

a. 6

b. 9

Step-by-step explanation:

a. The product modulo 7 can be found from the product of the individual numbers modulo 7:

(88·95·36·702) mod 7 = (88 mod 7)·(95 mod 7)·(36 mod 7)·(703 mod 7) mod 7

= (4·4·1·3) mod 7 = 48 mod 7 = 6

b. Powers of 4 mod 11 repeat with period 5:

4 mod 11 = 4

4^2 mod 11 = 5

4^3 mod 11 = 9

4^4 mod 11 = 3

4^5 mod 11 = 1

So, 4^83 mod 11 = 4^3 mod 11 = 9

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4c(2x+3) is my question. How to answer?

Shkiper50 [21]

Answer:

8cx + 12c

Step-by-step explanation:

Multiply the parentheses by 4 and then calculate the products

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3 years ago

At a store, Michael and Tonya bought bananas.

Anton [14]

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Let x be the cost of banana

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3 years ago

The table below shows two equations:

CaHeK987 [17]

Answer:

The solutions to equation 1 are x = 3, −1.5, and equation 2 has no solution.

Step-by-step explanation:

Rearranging the two equations, you get ...

|4x -3| = 9 . . . . . has two solutions
|2x +3| = -5 . . . . has no solutions (an absolute value cannot be negative)

The above-listed answer is the only one that matches these solution counts.

_____

Testing the above values of x reveals they are, indeed, solutions to Equation 1.

4 0

3 years ago

Read 2 more answers

Find the zeros of y = x + 6x- 4 by completing the square.

dsp73

Answer:

$\large\boxed{x=-3\pm\sqrt{13}}$

Step-by-step explanation:

$(a+b)^2=a^2+2ab+b^2\qquad(*)\\\\\\x^2+6x-4=0\qquad\text{add 4 to both sides}\\\\x^2+2(x)(3)=4\qquad\text{add}\ 3^2=9\ \text{to both sides}\\\\\underbrace{x^2+2(x)(3)+3^2}_{(*)}=4+9\\\\(x+3)^2=13\Rightarrow x+3=\pm\sqrt{13}\qquad\text{subtract 3 from both sides}\\\\x=-3\pm\sqrt{13}$

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3 years ago

Answer asap plz

babunello [35]

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3 years ago