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3 years ago

For a-b, reduce to the least non-negative residue

Mathematics

1 answer:

Olenka [21]3 years ago

3 0

Answer:

a. 6

b. 9

Step-by-step explanation:

a. The product modulo 7 can be found from the product of the individual numbers modulo 7:

(88·95·36·702) mod 7 = (88 mod 7)·(95 mod 7)·(36 mod 7)·(703 mod 7) mod 7

= (4·4·1·3) mod 7 = 48 mod 7 = 6

b. Powers of 4 mod 11 repeat with period 5:

4 mod 11 = 4

4^2 mod 11 = 5

4^3 mod 11 = 9

4^4 mod 11 = 3

4^5 mod 11 = 1

So, 4^83 mod 11 = 4^3 mod 11 = 9

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Dawn has 5\6 yard of lace. She uses 4\5 of it on a dress and the rest on a jewel box. How much does she use on the jewel box

mr_godi [17]

Answer:

Jewelry box: 1/6 yard

Step-by-step explanation:

4/5 (not 4\5) of her 5/6 yard goes into a dress: (4/5)(5/6 yd) = 2/3 yard.

This is the same as 4/6 yard. The amount of lace remaining, to be used on a jewelry box, is 5/6 - 4/6, or 1/6 yard.

3 0

3 years ago

Someone plz help me !!

Katarina [22]

Answer:

The greatest common factor of 64 and 72 is 8.

4 0

3 years ago

Let f(x) = x + 7 and g(x) = x − 4. Find f(x) ⋅ g(x). (1 point) x2 − 3x −28 x2 − 3x − 11 x2 + 3x − 28 x2 + 3x − 11

slavikrds [6]

$f(x)=x+7\\g(x)=x-4\\f(x)*g(x)=(x+7)(x-4)\\f(x)*g(x)=x^2+3x-28$

So it's x^2+3x-28

3 0

3 years ago

4. In a sample of 1000 people, 130 can wiggle their ears. Two unrelated people are

Elina [12.6K]

Using the hypergeometric distribution, it is found that there is a 0.7568 = 75.68% probability that neither can wiggle his or her ears.

The people are chosen from the sample without replacement, which is why the <u>hypergeometric distribution</u> is used to solve this question.

Hypergeometric distribution:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.
N is the size of the population.
n is the size of the sample.
k is the total number of desired outcomes.

In this problem:

1000 people means that $N = 1000$
130 can wiggle their ears, thus $k = 130$
Two are selected, thus $n = 2$ .

The probability that neither can wiggle his or her ears is P(X = 0), thus:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}$

$P(X = x) = h(0,1000,2,130) = \frac{C_{130,0}C_{870,2}}{C_{1000,2}} = 0.7568$

0.7568 = 75.68% probability that neither can wiggle his or her ears.

A similar problem is given at brainly.com/question/24826394

5 0

2 years ago

a car deceased in value by 25% in the first year. purchased for $28,000, what is the car worth today.

Gwar [14]

Try this: Principal times (1+interest rate as a decimal fraction)^(number of yrs)

In this case, Principal = $28,000; interest rate = -0.25; # of years = 1

So Decrease in value = $28,000 (0.75)^1 = $21,000.

4 0

3 years ago