Please answer asap!! What are three consecutive integers that have a sum of -51 ??

Mathematics

1 answer:

Setler79 [48]3 years ago

7 0

Answer:

-18, -17, -16

Step-by-step explanation:

Let’s assign x to be our main integer. The next consecutive integer to x is x+1, and the third one after that is x+2. Add everything together and set it equal to -51: 3x+3 = -51

Now, solve for x: x = -18

Add one and add two to -18 to get the rest of your answer:

-18 + 1 = -17

-18 + 2 =-16

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$\bf \begin{array}{cccll}\stackrel{x}{n}&term&\stackrel{y}{value}\\\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\1&a_1&-10\\\\2&a_2&\stackrel{-10+3}{-7}\\\\3&a_3&\stackrel{-7+3}{-4}\\\\4&a_4&\stackrel{-4+3}{-1}\\\\5&a_5&\stackrel{-1+3}{2}\\\\6&a_6&\stackrel{2+3}{5}\end{array}$