Given: ABCDis a parallelogram ∠GEC ≅ ∠HFA and AE ≅FC. Prove △GEC ≅ △HFA.
2 answers:
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Assuming the function is
For
to be differentiable, it necessarily has to be continuous. For this condition to be met, we need
For the derivative to exist, the one-sided limits of the derivative must also exist and be equal. We have
Now we solve for
and 
:
For
For the derivative to exist, the one-sided limits of the derivative must also exist and be equal. We have
Now we solve for
Answer:
<h2>Check out the image.</h2>Step-by-step explanation:
Let, the equation of the straight line is y = mx + c; where m is the slope of the equation and c is the constant.
The line has the slope 1.
Hence, the equation becomes y = x + c.
Since, the line passes through (-6, -2), -2 = -6 + c or, c = 4.
Hence, the equation of the straight line becomes y = x + 4.
Putting x = 0, we get, y = 4.
The line passes through (0, 4).
