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MrRissso [65]
2 years ago
9

Given: ABCDis a parallelogram ∠GEC ≅ ∠HFA and AE ≅FC. Prove △GEC ≅ △HFA.

Mathematics
2 answers:
sergejj [24]2 years ago
8 0

Already answered here: brainly.com/question/26860297

Karolina [17]2 years ago
7 0

<GEC=<HFA

As

  • A E=F C
  • A F=E C

Also

  • GE=FH

Henceforth

△GEC ≅ △HFA(SAS congruency)

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inysia [295]

Answer:

8 inches.

Step-by-step explanation:

From the statement we have that they first made two identical square pyramids, each with a base area of 100 square inches.

Ab = s ^ 2 = 100

Therefore each side would be:

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So, side of the square base = 10 inches

Then they tell us that they glued the bases of the pyramids together to form the precious stone. The surface area of the gemstone is 520 square inches, so for a single pyramid it would be:

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For an area of the square pyramid we have the following equation:

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2 years ago
Simply please “picture”
oksian1 [2.3K]
<h3>Answer: (-infinity, 7]</h3>

=====================================

Explanation:

The first interval (-infinity, 3) describes any number less than 3, so we can write x < 3 in short hand (where x is the unknown number).

The second interval (-1, 7] means we start at -1 and stop at 7. We do not include -1 but include 7. So we say that -1 < x \le 7 (ie x is between -1 and 7; exclude -1, include 7)

If you were to graph each ona number line, you would see that the too intervals have overlapping parts. The right most edge extends out as far as x = 7. There is no left most edge as it goes onforever that direction.

Therefore, the to intervals combine to get x \le 7 which turns into the interval notation answer of (-infinity, 7]

-----------

It might help to think of it like this: x < 3 and -1 < x \le 7 say "x is some number that is less than 3, or it is between -1 and 7". So x could be anything less than 7, including 7 itself.

4 0
3 years ago
What is 6÷319 step by step​
Kipish [7]

6/319 = 0.0188087774

I used a calculator

or, just use long division

Have a great day!

Stay safe and healthy!

Happy holiday seasons!

May I please have brainliest?

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Which domain restrictions apply to the rational expression?
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1) it must be fulfilled that the denominator is different from zero, then for this expression

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