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Vedmedyk [2.9K]
3 years ago
5

Find an equation of the line passing through the given points (1,-3) and (3,3)

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
6 0

ANSWER: y= 3x - 6

STEP-BY-STEP EXPLANATION:

(1,-3) and (3,3)

X1=1           X2=3

Y1= - 3       Y2=3

1) Find the slope of the line.

To find the slope of the line passing through these two points we need to use the slope  formula:

m = \frac{Y2-Y1}{X2-X1}

m= \frac{3-(-3)}{3-1}   m=\frac{6}{2} = 3

2)Use the slope to find the y-intercept.

Now that we know the slope of the line is 3 we can plug the slope into the equation and  we get:

y= 3x+b

Next choose one of the two point to plug in for the values of x and y. It does not matter  which one of the two points you choose because you should get the same answer in either  case. I generally just choose the first point listed so I don’t have to worry about which  one I should choose.

y= 3x+b       point (1,-3)

-3= 3(1) + b

-3-3=b

-6=b

3)Write the answer.

Using the slope of 3 and the y-intercept of -6 the answer is:

y = 3x - 6

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A^2 + b^2 + c^2  - ab - bc - ca = 0
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3 years ago
Need help again asap please! Find the sum of the first 30 terms of the sequence below an=3n+2
hoa [83]

S_{30} = 1455

generate a few terms of the sequence using a_{n} = 3n + 2

a_{1} = ( 3 × 1) + 2 = 5

a_{2} = (3 × 2) + 2 = 8

a_{3} = (3 × 3 ) + 2 = 11

a_{4} = (3 × 4 ) + 2 = 14

a_{5} = ( 3 × 5 ) + 2 = 17

the terms are 5, 8, 11, 14, 17

these are the terms of an arithmetic sequence

sum to n terms is calculated using S_{n} = \frac{n}{2} [ 2a + (n-1)d]

where a is the first term and d the common difference

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S_{30} = \frac{30}{2} [( 2 × 5) + (29 × 3) ]

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3 0
3 years ago
Read 2 more answers
X-3/35=2/15 please help me and answer it with an explanation
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I believe x = 23/105 because you would have to add 3/35 to both sides and when you add 2/15 to 3/35 you get an answer of 23/105.

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6 0
3 years ago
Unit 8: Right Triangles &amp; Trigonometry<br> Homework 2: Special Right Triangles
Kamila [148]

Answer:

17. z=39/sin45=78/\sqrt{2}

    y=39/tan60=39/\sqrt{3}

    x=y/sin60=78/\sqrt{3}

19. x=6\sqrt{3}/tan60=6

    y=2x=12

    z=\sqrt{2}y=12\sqrt{2}

Step-by-step explanation:

17.

because:sin45=39/z    

so:     z=39/sin45=78/\sqrt{2}

then: tan60=39/y

so:    y=39/tan60=39/\sqrt{3}

last:  sin60=y/x

so:    x=y/sin60=78/\sqrt{3}

19.

because: tan60=6\sqrt{3}/x

so:            x=6\sqrt{3}/tan60=6

then:        sin30=x/y

so:            y=x*sin30=2x=12

last:          sin45=y/z

so:            z=sin45*y=\sqrt{2}y=12\sqrt{2}

   

4 0
2 years ago
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