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IceJOKER [234]
3 years ago
8

8. The logo for a company is a regular hexagon inscribed inside a circle. The logo will

Mathematics
1 answer:
fgiga [73]3 years ago
5 0

Divide the hexagon into 6 equal streak triangles which would have side length equal to the radius of the circle.


the area of an equal lateral triangle = sqrt(3)/4 x radius^2


the area of the hexagon would be 6 x sqrt(3)/4 x radius^2


Area = 6 x sqrt(3)/4 x 8^2 = 166.2768 square feet


rounded to the nearest whole foot = 166 square feet.

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3/4 + -3/8 + -1/4=?<br> Evaluate the expression
Ann [662]

Answer: -1/8

Step-by-step explanation:

3/4 + -3/8 + -1/4

Find the LCM of 4, 8, and 4

That's 8 so you make an equivalent fraction for all fractions so the denominator is 8.

3/4 = 6/8

-3/8 = -3/8

-1/4 = -4/8

Now the expression looks like this:

6/8 + - 3/8 + -4/8

6/8 - 3/8 - 4/8

6/8 - 7/8

-1/8

Hope that helped!

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Kevin says it will take him less than 1 hour to do homework and play soccer is he correct? Explain.
babunello [35]

Answer:

I don't know how I would know but if he takes 30 minutes or less on each individual activity then he is correct, if he exceeds those limits, he is incorrect.

Step-by-step explanation:

3 0
3 years ago
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never [62]

Answer: 1145 feets

Step-by-step explanation:

The total feet of streamer that Shirley have to decorate with will be the addition of the total roll of blue streamer plus the total roll of green streamer. This will be:

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Ok, so 120 pages plus the 60% of the book she has left to read will give the total number of pages.

That means that 120 pages is 40% of the book.

Make a proportion

120/40% = x/60%

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x = 180 pages
5 0
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Read 2 more answers
Solve the equation on the interval [0,2π]
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\bf 8sin^4(x)+1-6sin^2(x)=0\implies 8sin^4(x)-6sin^2(x)+1=0

now, this is a quadratic equation, but the roots do not come out as integers, however it does have them, the discriminant, b² - 4ac, is positive, so it has 2 roots, so we'll plug it in the quadratic formula,

\bf 8sin^4(x)-6sin^2(x)+1=0\implies 8[~[sin(x)]^2~]^2-6[sin(x)]^2+1=0&#10;\\\\\\&#10;~~~~~~~~~~~~\textit{quadratic formula}&#10;\\\\&#10;\begin{array}{lcccl}&#10;& 8 sin^4& -6 sin^2(x)& +1\\&#10;&\uparrow &\uparrow &\uparrow \\&#10;&a&b&c&#10;\end{array} &#10;\qquad \qquad &#10;sin(x)= \cfrac{ -  b \pm \sqrt {  b^2 -4 a c}}{2 a}&#10;\\\\\\&#10;sin(x)=\cfrac{-(-6)\pm\sqrt{(-6)^2-4(8)(1)}}{2(8)}\implies sin(x)=\cfrac{6\pm\sqrt{4}}{16}&#10;\\\\\\&#10;sin(x)=\cfrac{6\pm 2}{16}\implies sin(x)=&#10;\begin{cases}&#10;\frac{1}{2}\\\\&#10;\frac{1}{4}&#10;\end{cases}

\bf \measuredangle x=&#10;\begin{cases}&#10;sin^{-1}\left( \frac{1}{2} \right)&#10;sin^{-1}\left( \frac{1}{4} \right)&#10;\end{cases}\implies \measuredangle x=&#10;\begin{cases}&#10;\frac{\pi }{6}~,~\frac{5\pi }{6}\\&#10;----------\\&#10;\approx~0.252680~radians\\&#10;\qquad or\\&#10;\approx~14.47751~de grees\\&#10;----------\\&#10;\pi -0.252680\\&#10;\approx 2.88891~radians\\&#10;\qquad or\\&#10;180-14.47751\\&#10;\approx 165.52249~de grees&#10;\end{cases}
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