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3 years ago

Write a problem that can be solved with a bar model that shows equal groups of liters

Mathematics

1 answer:

allochka39001 [22]3 years ago

6 0

Bar models are used to illustrate products and quotients

The equation modeled by the bar is $5 x = 10$

<h3>How to describe the bar</h3>

The bar is not given.

So, I will use the attached figure to solve the question

From the attached figure, we have the following highlights:

The length of the bar is 10 units
Each bar is x unit long
There are 5 rectangles/squares in the model

So, the equation of the bar is:

$5 * x = 10$

Multiply 5 and x

$5 x = 10$

Hence, the equation modeled by the bar is $5 x = 10$

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Which of the following represents a function

tatuchka [14]

Answer:

Step-by-step explanation:

A has -1 going to two different y values so it is not a function

B has x = -1 going to two different y values so it is not a function

C has the input of 3 going to two different y values so it is not a function

D each input goes to only 1 output so it is a function

6 0

3 years ago

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5. Is the sequence arithmetic? If so, identify the common difference.

HACTEHA [7]

5.
aritmetic is same increase per term
14 to 21 is 7
21 to 42 is 21
7≠21
no

6.
decreases by 4 each time
an=a1+d(n-1)
an=10-4(n-1)
n=12 for 12th term
a12=10-4(12-1)
a12=10-4(11)
a12=10-44
a12=-34

it is -34

7.
missing term is y
22+n=y
y+n=34
22+n+n=34
22+2n=34
minus 22 from both sides
2n=12
divide both sides by 2
n=6
22+n=y
22+6=y
28=y

28 is answer

5. no
6. -34
7. 28

6 0

4 years ago

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Subtract -7a^2 + 3a -9 from 5a^2 - 6a -4<br><br> Answer should be polynomial in standard form

lara [203]

5a^2 - 6a -4 - (<span>-7a^2 + 3a -9)
=</span>5a^2 - 6a -4 + 7a^2 - 3a + 9
=12a^2 - 9a + 5

answer
12a^2 - 9a + 5

6 0

3 years ago

Brainliest to best answer (:

grigory [225]

Its C
A positive intercept of 4
A solid line because of the equal to part
And shading down because of the sign direction

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3 years ago

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What is cos 30?<br>this is geometry

nirvana33 [79]

So the definition of the cosine of an angle of a right triangle is $\frac{adjacent}{hypotenuse}$ . You may remember this by SohCahToa (sine is opposite over hypotenuse, cosine is adjacent over hypotenuse, tangent is opposite over adjacent).

Remember, adjacent refers to the side next to the angle in question, and the side can't also be the hypotenuse. The hypotenuse is that longest side and is opposite the right angle.

We have the cosine of 30°. We write

$\cos(30)= \frac{adj}{hyp} = \frac{ \sqrt{3}}{2}$

8 0

3 years ago

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