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Romashka [77]
3 years ago
5

The difference between 8 forty-sevens and forty-sevens

Mathematics
1 answer:
melisa1 [442]3 years ago
6 0
847 s - 47 I think that’s what it is
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Pls help ASAP will give brainlies
vagabundo [1.1K]

Answer:

The answer is the third selection

Step-by-step explanation:

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Can somebody tell me how to do this?
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I'm pretty sure that 20 is 5 but other than that, I can't help with anymore.
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Write the following decimal number in its equivalent fraction form. Show all work for full credit.
svetoff [14.1K]

Answer:

8/9

dont want full credit just want points

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Aakarshini Nemali You wrote 19 hours ago. ​hi mrs. e, i was wondering if you could help me understand this question from the usa
ExtremeBDS [4]

Answer:

x^{2} +y^{2}-6y-12x+43=0

Step-by-step explanation:

The general form of the equation of a circle is given as:

(x-a)^2+(y-b)^2=r^2 where (a,b) are the centre and r is the radius.

If (5, 4) and (7, 2) are the endpoints of a diameter, we find the coordinate of the centre using the midpoint formula.

\frac{1}{2}(x_1+x_2 , y_1+y_2) \:where (x_1,y_1 \:and\: x_2, y_2) are the two points.

Midpoint of (5, 4) and (7, 2) = \frac{1}{2}(5+7 , 4+2) =\frac{1}{2}(12 , 6)=(6,3)

Next, we determine the radius. Using the distance formula, we find the distance from the centre to any of the endpoints.

Distance from (5,4) to (6,3)

r=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2} \\

=\sqrt{(5-6)^2+(4-3)^2} \\=\sqrt{(-1)^2+(1)^2}=\sqrt{1+1}=\sqrt{2}\\r=\sqrt{2}

The equation of the circle centre (6,3) with radius \sqrt{2} is therefore given as:

(x-a)^2+(y-b)^2=r^2\\(x-6)^2+(y-3)^2=(\sqrt{2}) ^2\\x^{2} +y^{2}-6y-12x+45=2\\x^{2} +y^{2}-6y-12x+45-2=0\\x^{2} +y^{2}-6y-12x+43=0

6 0
3 years ago
In the diagram, rectangle ABCD has a perimeter of 20 cm.<br><br>What is the area of ADEC?​
Klio2033 [76]

Answer:

the answer is 50cm

Step-by-step explanation:

x=5

so 5+5 would be 10

so the long side would be 10 and the short side would be 5

so 5cmx10cm= 50cm

7 0
3 years ago
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