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Yuliya22 [10]
2 years ago
9

In an isosceles triangle, the angle formed by its legs is called__

Mathematics
2 answers:
Alecsey [184]2 years ago
7 0

Answer:

a:vertex angle

Step-by-step explanation:

it is vertex angle

nasty-shy [4]2 years ago
7 0

\large\bf\blue{answer}

In an isosceles triangle, the angle formed by its legs is called vertex angle

<u>option </u><u>a </u><u>is </u><u>correct </u>

<h3>i hope it helped u</h3>

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Nesterboy [21]

Answer:

solution

here,

<h3>the power of route 216 of 6 is 6to the power 3</h3>
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1 year ago
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Which is the value of the expression (StartFraction (10 Superscript 4 Baseline) (5 squared) Over (10 cubed) (5 cubed)) cubed?
Flura [38]

Answer:

The value to the given expression is 8

Therefore \left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=8

Step-by-step explanation:

Given expression is (StartFraction (10 Superscript 4 Baseline) (5 squared) Over (10 cubed) (5 cubed)) cubed

Given expression can be written as below

\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3

To find the value of the given expression:

\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=\frac{((10^4)(5^2))^3}{((10^3)(5^3))^3}

( By using the property ((\frac{a}{b})^m=\frac{a^m}{b^m} )

=\frac{(10^4)^3(5^2)^3}{(10^3)^3(5^3)^3}

( By using the property (ab)^m=a^mb^m )

=\frac{(10^{12})(5^6)}{(10^9)(5^9)}

( By using the property (a^m)^n=a^{mn} )

=(10^{12})(5^6)(10^{-9})(5^{-9})

( By using the property \frac{1}{a^m}=a^{-m} )

=(10^{12-9})(5^{6-9}) (By using the property a^m.b^n=a^{m+n} )

=(10^3)(5^{-3})

=\frac{10^3}{5^3} ( By using the property a^{-m}=\frac{1}{a^m} )

=\frac{1000}{125}

=8

Therefore \left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=8

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3 0
3 years ago
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He lost 8, so he is at -8, he then gains 15 so add 15 to -8"-8 + 15 = 7

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