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3 years ago

5х2-7x-6=0 factored form

Mathematics

1 answer:

Vinvika [58]3 years ago

8 0

Answer:

(x - 2)(5x + 3) = 0

Step-by-step explanation:

5x² - 7x - 6 = 0

Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 5 × - 6 = - 30 and sum = - 7

The factors are - 10 and + 3

Use these factors to split the x- term

5x² - 10x + 3x - 6 = 0 ( factor the first/second and third/fourth terms )

5x(x - 2) + 3(x - 2) = 0 ← factor out (x - 2) from each term

(x - 2)(5x - 3) = 0 ← in factored form

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Compare 1/2 with 3/4 using ( <,>,=)

irga5000 [103]

1/2 < 3/4

1/2 is = 2/4

and 2/4 < 3/4
therefore 1/2 must be < 3/4

5 0

3 years ago

Read 2 more answers

Joanie runs the concession stand for the school's baseball games. At each game, the best selling items are pretzels and hot dogs

Elenna [48]

X is pretzels and y is hot dogs
3x + 2y=195
x +15 =y

3x + 2(x+15)=195
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3 years ago

Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviat

drek231 [11]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

Step-by-step explanation:

For this case we have the following probability distribution given:

X 0 1 2 3 4 5

P(X) 0.031 0.156 0.313 0.313 0.156 0.031

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

We can verify that:

$\sum_{i=1}^n P(X_i) = 1$

And $P(X_i) \geq 0, \forall x_i$

So then we have a probability distribution

We can calculate the expected value with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

6 0

3 years ago

Please someone help!! I tried my best to complete this problem but i'm stuck now (also am i even doing it right so far??!);(

Alik [6]

Answer and Step-by-step explanation:

You got everything correct so far except for #4.

4. Yes, it is 1. But it would be in months.

So you would put:

1 month = x

12 months = 1 year.

Since the population increases by 1.5 times a <em>month.</em>

For question number 3.

The equation should be:

$f(x) = 100(1.5)^x$ <- Function

$f(x) = 100(1.5)^{12}$ <- Function when x is 12 months (1 year)

(Put those both the same way I put it.)

It gives you the equation to work with, you just have to plug in the values.

1.5 is in the parenthesis because it needs to be the one that is raised by an exponent.

100 is the initial population, so it stays on the outside.

x is the exponent

7 0

3 years ago

PLZ HELPP!!!!

Kisachek [45]

Answer: its A

Step-by-step explanation:i did the test

4 0

3 years ago