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Marina86 [1]
3 years ago
11

Please someone help!! I tried my best to complete this problem but i'm stuck now (also am i even doing it right so far??!);(

Mathematics
1 answer:
Alik [6]3 years ago
7 0

Answer and Step-by-step explanation:

You got everything correct so far except for #4.

4. Yes, it is 1. But it would be in months.

So you would put:

1 month = x

12 months = 1 year.

Since the population increases by 1.5 times a <em>month.</em>

For question number 3.

The equation should be:

f(x) = 100(1.5)^x <- Function

f(x) = 100(1.5)^{12} <- Function when x is 12 months (1 year)

(Put those both the same way I put it.)

It gives you the equation to work with, you just have to plug in the values.

1.5 is in the parenthesis because it needs to be the one that is raised by an exponent.

100 is the initial population, so it stays on the outside.

x is the exponent

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3 years ago
Find the missing lengths: LK=15 and KH=9, find KI and HI.
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Answer:

KI=11.25 and HI=6.75

Step-by-step explanation:

Consider the below figure attached with this question.

According to Pythagoras Theorem:

base^2+perpendicular^2=hypotenuse^2

Use Pythagoras in triangle HKL

LH^2+KH^2=LK^2

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Taking square root on both sides.

LH=12

Let length of HI be x.

LI = 12+x

Use Pythagoras theorem in ΔKLI,

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(KI)^2+225=x^2+24x+144

(KI)^2=x^2+24x+144-225

(KI)^2=x^2+24x-81...(1)

Use Pythagoras theorem in ΔHKI,

(KI)^2=x^2+9^2

(KI)^2=x^2+81...(2)

From (1) and (2) we get

x^2+81=x^2+24x-81

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x=\dfrac{162}{24}=6.75

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Substitute x=6.75 in equation (2).

(KI)^2=(6.75)^2+81

(KI)^2=126.5625

Taking square root on both sides.

KI=\sqrt{126.5625}

KI=11.25

Hence, the measure of KI is 11.25 units.

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