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2 years ago

How many liters of soup will fit in this hemispherical pot PlS help

Mathematics

1 answer:

m_a_m_a [10]2 years ago

4 0

Answer:

3888pi cm^3 or 12214.5122372 cm^3

Step-by-step explanation:

To being, let's list out what we know

The volume of a sphere is

V = 4/3(pir^3)

But this is only half of a sphere, so the volume of it should be

V =2/3(pir^3)

With the diameter of the shape being

d = 36

We will first need to find the radius to use the formula above

r = d / 2

= 36 / 2

= 18

Now, let's start plugging in values

V = 2/3(pi18^3)

= 2/3 ( 5832pi)

= 3888pi or 12214.5122372

If you have any questions, please let me know in the comments section of this answer! If you could mark this answer as the brainliest, I would greatly appreciate it! :D

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Which expression is equivalent -8-(-12)

asambeis [7]

Answer:

Step-by-step explanation:

-8-(-12)=4

1.8-12=-4

2.-8+12=4

3.-8-12=-20

4.-(8+12)=-4

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3 years ago

Answer this questions right and i will give you Brainliest, Thanks, and 5 stars and thanks on profile.

katen-ka-za [31]

Answer:

1. k=5

2. a= -7

3. n=4

4. n=1

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6. r= -4

7. b=31

8.n= -3

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2 years ago

What is two plus two

alisha [4.7K]

Answer:

4??? lol

Step-by-step explanation:

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3 years ago

Read 2 more answers

A parent volunteer group is raising money by making custom hats to sell at school activities.they plan to sell the hats for $10.

Hunter-Best [27]

Answer:

Money raised($)= 6n-50

Step-by-step explanation:

they plan to sell the hats for $10. each hat $4 to make and they spend $50 for advertising.

If their are no number of hats

Cost = 50+4n

Money gotten from the n number of hats= 10(n)

If they are to make profit, the money gotten from the sales of hats should be bigger than the total cost

Money raised = money from sales- cost

Money raised= 10n -4n-50

Money raised($)= 6n-50

8 0

3 years ago

A market research team thinks that their new ad campaign is better than their old one. They used to be able to sell to 50% of th

andreev551 [17]

Answer:

a. The test statistic is 2 and we conclude that the new ad campaign is not signficantly better.

Step-by-step explanation:

They used to be able to sell to 50% of those who saw their ads. Test if the new campaign is better.

At the null hypothesis, we test is it is the same, that is, the proportion is the same.

$H_0: p = 0.5$

At the alternate hypothesis, we test if it is significantly better, that is, the proportion is above 50%.

$H_1: p > 0.5$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.5 is tested at the null hypothesis:

This means that $\mu = 0.5, \sigma = \sqrt{0.5*0.5} = 0.5$

They take a random sample of 100 potential buyers and find that they convinced 60 of these people to buy their product.

This means that $n = 100, X = \frac{60}{100} = 0.6$

Test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.6 - 0.5}{\frac{0.5}{\sqrt{100}}}$

$z = 2$

The test statistic is 2.

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion above 0.6, which is 1 subtracted the by p-value of z = 2.

Looking at the z-table, z = 2 has a p-value of 0.9772.

1 - 0.9772 = 0.0228.

The p-value of the test is 0.0228 > 0.01, which means that we cannot conclude that the new ad campaign is signficantly better, so the correct answer is given by option A.

5 0

3 years ago