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diamong [38]
3 years ago
14

You are given the coordinates of four points that are the vertices of a parallelogram. You need to determine if the parallelogra

m is a rhombus. Explain how you could determine this.
Mathematics
1 answer:
Fantom [35]3 years ago
8 0
A rhombus is a parallelogram, namely, is a polygon with four sides and two pairs of parallel sides.

the one distinction of a rhombus with other parallelograms is that, a rhombus has all equal sides, all its four sides are the same length, so, if you already know the vertices are for a parallelogram, then is a given two pairs of sides are parallel.

so...  you simply need to check their length, making sure they're all equal, using the distance formula.
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5(x+4)> 2x-7 solve the inequality
galina1969 [7]

Answer:

-9>x

Step-by-step explanation:

5(x+4)>2x-7

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Step-by-step explanation:

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3 years ago
The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a st
Alinara [238K]

Answer:

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.

In this problem

The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so \mu = 0.5, \sigma = 0.05.

What is the probability that a line width is greater than 0.62 micrometer?

That is P(X > 0.62)

So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.62 - 0.5}{0.05}

Z = 2.4

Z = 2.4 has a pvalue of 0.99180.

This means that P(X \leq 0.62) = 0.99180.

We also have that

P(X \leq 0.62) + P(X > 0.62) = 1

P(X > 0.62) = 1 - 0.99180 = 0.0082

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

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