Remember that
If the given coordinates of the vertices and foci have the form (0,10) and (0,14)
then
the transverse axis is the y-axis
so
the equation is of the form
(y-k)^2/a^2-(x-h)^2/b^2=1
In this problem
center (h,k) is equal to (0,4)
(0,a-k)) is equal to (0,10)
a=10-4=6
(0,c-k) is equal to (0,14)
c=14-4=10
Find out the value of b
b^2=c^2-a^2
b^2=10^2-6^2
b^2=64
therefore
the equation is equal to
<h2>(y-4)^2/36-x^2/64=1</h2><h2>the answer is option A</h2>
Which ever on is on the whole side of the side of the decimal...or in other words, what ever number is on the left side of the decimal
First generation: 3
Second generation:
Third generation:
Fourth generation:
And so on. The general formula for the
th generation is
. So by the 15th generation, you should expect around
geese.
Answer:
The answer is Quadrant I.
Step-by-step explanation:
Start from the upper left square to the right and go to the bottom left square after you move from there.
Quadrant I is like Quadrant 1. Quadrant II is like Quadrant 2 and so forth. So if each Quadrant is the square with the lines dividing it, your answer is Quadrant I.
Answer
14/27
Step-by-step explanation:
4/9 / 7/6 = 14/27
