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lutik1710 [3]
2 years ago
9

Which of the following is not preserved under a dilation?

Mathematics
1 answer:
Helga [31]2 years ago
3 0
C distance is the only thing that isn't preserved under a dilation

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the perimeter of a triangle is 38 ft . One side is 14 ft long . Another side is 9 ft long . How long is the third side ?
Aleks [24]
38 - (14+9) = 15ft long
4 0
3 years ago
How to find the zeros of f(x)=5(2x-5)(5x+4)
Elenna [48]
If xy=0 we assume x and y equal 0

so

the zeros are wehre f(x)=0
0=5(2x-5)(5x+4)
set each to zero
5 is not equal 0 so we don't do that

0=2x-5
5=2x
5/2=x

0=5x+4
-4=5x
-4/5=x

zeroes at x=5/2 and -4/5
3 0
2 years ago
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F Tell whether the statement is true or false.
Kitty [74]

Answer:

A true

Step-by-step explanation:

It is the correct answer i have read this

7 0
3 years ago
The owner of an automobile insures it against damage by purchasing an insurance policy with a deductible of 250. In the event th
choli [55]

Answer:

Step-by-step explanation:

From the given information:

The uniform distribution can be represented by:

f_x(x) = \dfrac{1}{1500} ; o \le x \le   \  1500

The function of the insurance is:

I(x) = \left \{ {{0, \ \ \ x \le 250} \atop {x -20 , \ \  \ \ \ 250 \le x \le 1500}} \right.

Hence, the variance of the insurance can also be an account forum.

Var [I_{(x}) = E [I^2(x)] - [E(I(x)]^2

here;

E[I(x)] = \int f_x(x) I (x) \ sx

E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250) \ dx

= \dfrac{1}{1500 } \dfrac{(x - 250)^2}{2} \Big |^{1500}_{250}

\dfrac{5}{12} \times 1250

Similarly;

E[I^2(x)] = \int f_x(x) I^2 (x) \ sx

E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250)^2 \ dx

= \dfrac{1}{1500 } \dfrac{(x - 250)^3}{3} \Big |^{1500}_{250}

\dfrac{5}{18} \times 1250^2

∴

Var {I(x)} = 1250^2 \Big [ \dfrac{5}{18} - \dfrac{25}{144}]

Finally, the standard deviation  of the insurance payment is:

= \sqrt{Var(I(x))}

= 1250 \sqrt{\dfrac{5}{48}}

≅ 404

4 0
2 years ago
What is the vertex of the quadratic function f(x)=(x-6)(x+2)
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(2,-16) should be the answer
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