Find the equation of the line parallel to to -2x + 3y = 11 and passes through the points (3, -2)
1 answer:
Answer:
2x -3y = 12
Step-by-step explanation:
The parallel line will have the same variable coefficients, but a different constant appropriate to the given point. Using that point, we find the constant to be ...
-2x +3y = constant
-2(3) +3(-2) = -6 -6 = -12
The equation can be written ...
-2x +3y = -12
We prefer the "standard form", which has a positive leading coefficient. To get that, we can multiply the equation by -1.
2x -3y = 12
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