Answer:
a = √93
a ≈ 9.64
Step-by-step explanation:
We can use the Pythagorean theorem for this: a² + b² = c²
c is given as the hypotenuse, which is the pole with a length of 17 ft
c² is 17²
b is a leg with a height of 14 ft
b² = 14²
We need to find the base leg, a, distance from the wall to the base of the pole.
Solve:
a² + 14² = 17²
a² + 196 = 289
a² = 93
a = √93
-Chetan K
Amounttotal=amount per day times number of days
200=17.1 times d
divide both sides by 17.1
11.695=d
about 12 days
4.7 because if you plug it in- (2,1) and (6,6) it is 4.7 units
Answer:
45 feet
Step-by-step explanation:
To find the width of the model, we need to find the scale of the model to the actual tower.
Since we know the height of both towers, we can use that as the basis.
24 inches : 60 feet
12 inches : 30 feet
6 inches : 15 feet
So the width of the tower is 18 inches wide.
18 inches will then be equal to 12 + 7 inches : 30 + 15 feet
18 inches : 45 feet
You want to find values of v (number of visors sold) and c (number of caps sold) that satisfy the equation
... 3v + 7c = 4480
In intercept form, this equation is
... v/(1493 1/3) + c/640 = 1 . . . . . divide by 4480
Among other things, this tells us one solution is
... (v, c) = (0, 640)
The least common multiple of 3 and 7 is 21, so decreasing the number of caps sold by some multiple of 3 and increasing the number of visors sold by that same multiple of 7 will result in another possible solution.
The largest multiple of 21 that is less than 4480 is 213. Another possible solution is (0 +213·7, 640 -213·3) = (1491, 1)
We can also pick some number in between, say using 100 as the multiple
... (0 +100·7, 640 -100·3) = (700, 340)
In summary, your three solutions could be
... (visors, caps) = (0, 640), (700, 340), (1491, 1)
