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Troyanec [42]
2 years ago
5

How do you find the x value of an angle​

Mathematics
1 answer:
I am Lyosha [343]2 years ago
3 0

Answer:

Since the value of all angles within a triangle must equal 180 degrees, if you know at least two angles, you can subtract them from 180 to find the missing third angle. If you are working with equilateral triangles, divide 180 by three to find the value of X.

Step-by-step explanation:

I hope this helps you.

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If g(x)=70−3x, find -g(-x)
Vedmedyk [2.9K]

Answer:

- g(- x) = - 70 - 3x

Step-by-step explanation:

to evaluate g(- x) substitute x = - x into g(x)

g(- x) = 70 - 3(- x) = 70 + 3x, hence

- g(- x) = - (70 + 3x) = - 70 - 3x


6 0
3 years ago
How can you determine the slope and the y- intercept of a line from a graph?
Molodets [167]
Slope: Take two points from the graph, and do y-y, over x-x.

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6 0
3 years ago
Multiply and simplify. (5 - 3i)(6 + 2i)
AleksandrR [38]
36-8i is the answer.
3 0
3 years ago
Read 2 more answers
In parallelogram abcd, ab=14, bc=20, m(angle)b=54. Find to the nearest tenth the length of diagonal bd, and find measure angle d
muminat
It is is a parallelogram, hence we have to face sides equal in length and the opposite angles are also the same. From the given above we have:
ab=14 and its opposite side cd=14
bc=20 and its opposite side da=20

Solving for the diagonal measurement bd, we have consecutive angles are equal to 180°
∠A+∠B=180°
∠A=180°-54°
∠A=126° , ∠B=54° ,∠C=126° and ∠D=54°
bd²=ab²+da²-2(ab)(da)cos126°
bd²=14²+20²-2*14*20cos126°
bd=30.42 unit

Solving for the angle dbc, we have
cos dbc=bc²+bd²-cd²/a*bc*bd
cos dbc=20²+30.42²-14²/2*20*30.42
dbc=21.76° 
3 0
3 years ago
PLEASE HELP FOR BRAINLIEST! ;)
IrinaVladis [17]

1. D - Since it's random, everyone has an equal chance of being picked

2. B - Since the people are already registered voters it would be easier to get a response from them. Plus, picking ever 10th person makes it random.

3. false - a fair question wouldn't make assumptions about the population

4. B - "Don't you think" causes the answerer to be pushed towards saying yes

hope this helps :)

5 0
3 years ago
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