The amount of rim needed for each window is 141.4 in
<h3>How to find the length of the outer rim?</h3>
Since the outer rim is the length of an arc, we use the formula for length of an arc of a circle.
<h3>What is an arc?</h3>
An arc is part of section of the circumference of a circle
<h3>What is the length of an arc?</h3>
So, length of arc, L = Ф/360 × 2πR where
- Ф = central angle of arc and
- R = radius of circle.
Gven that for the window rim
- Ф = angle of the rim = 270° and
- R = radius of the rim = 30 in
Substituting the values of the variables into the equation for L, we have
L = Ф/360 × 2πR
L = 270°/360° × 2π × 30 in
L = 3/4 × 2π × 30 in
L = 3/2 × π × 30 in
L = 3 × π × 15 in
L = 45π in
L = 141.37 in
L ≅ 141.4 in
So, the amount of rim needed for each window is 141.4 in
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15<span>√2 is what I got for the answer.</span>
Answer:
The answer is
Step-by-step explanation:
Answer:
x=9, y=15. (9, 15).
Step-by-step explanation:
y=2x-3
y=x+6
----------
2x-3=x+6
2x-x-3=6
x-3=6
x=6+3
x=9
y=9+6=15
The volume and surface area of the pyramid will be 392 / 3 cubic units and 189 square units. Then the correct option is A.
The complete question is attached below.
<h3>What is the volume and surface area of the pyramid? </h3>
Suppose the base of the pyramid has length = L units, width = W units, slant height = K units, and the height of the pyramid is of H units.
Then the volume of the pyramid will be
V = (L × B × H) / 3
The surface area of the pyramid will be
SA = 2(1/2 × B × K) + 2(1/2 × L × K) + (L × B)
Then the volume will be
V = (7 × 7 × 8) / 3
V = 392/3 cubic units
Then the surface area will be
SA = 2(1/2 × 7 × 10) + 2(1/2 × 7 × 10) + (7 × 7)
SA = 189 square units
Then the correct option is A.
More about the volume and surface area of the pyramid link is given below.
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