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Elena-2011 [213]
4 years ago
6

In the diagram below QT =7 which additional facts would guarantee that QRST is a parallelogram check all that apply

Mathematics
2 answers:
lions [1.4K]4 years ago
4 0

Answer: A. QT is parallel to RS and C. QR =5, ST=5

nlexa [21]4 years ago
3 0

Answer:

option A and C

QT is parallel to RS

QR = 5 , ST = 5

Step-by-step explanation:

The definition of a parallelogram is as below

A parallelogram is a quadrilateral with 2 pairs of opposite, equal and parallel sides.

To prove a quadrilateral is a parallelogram, one of these five ways is to prove that one pair of opposite sides is both congruent and parallel.

And ways is to prove that both pairs of opposite sides are congruent.

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1. Consider an athlete running a 40-m dash. The position of the athlete is given by , where d is the position in meters and t is
sasho [114]

There is some information missing in the question, since we need to know what the position function is. The whole problem should look like this:

Consider an athlete running a 40-m dash. The position of the athlete is given by d(t)=\frac{t^{2}}{6}+4t where d is the position in meters and t is the time elapsed, measured in seconds.

Compute the average velocity of the runner over the intervals:

(a) [1.95, 2.05]

(b) [1.995, 2.005]

(c) [1.9995, 2.0005]

(d) [2, 2.00001]

Answer

(a) 6.00041667m/s

(b) 6.00000417 m/s

(c) 6.00000004 m/s

(d) 6.00001 m/s

The instantaneous velocity of the athlete at t=2s is 6m/s

Step by step Explanation:

In order to find the average velocity on the given intervals, we will need to use the averate velocity formula:

V_{average}=\frac{d(t_{2})-d(t_{1})}{t_{2}-t_{1}}

so let's take the first interval:

(a) [1.95, 2.05]

V_{average}=\frac{d(2.05)-d(1.95)}{2.05-1.95}

we get that:

d(1.95)=\frac{(1.95)^{3}}{6}+4(1.95)=9.0358125

d(2.05)=\frac{(2.05)^{3}}{6}+4(2.05)=9.635854167

so:

V_{average}=\frac{9.6358854167-9.0358125}{2.05-1.95}=6.00041667m/s

(b) [1.995, 2.005]

V_{average}=\frac{d(2.005)-d(1.995)}{2.005-1.995}

we get that:

d(1.995)=\frac{(1.995)^{3}}{6}+4(1.995)=9.30335831

d(2.005)=\frac{(2.005)^{3}}{6}+4(2.005)=9.363335835

so:

V_{average}=\frac{9.363335835-9.30335831}{2.005-1.995}=6.00000417m/s

(c) [1.9995, 2.0005]

V_{average}=\frac{d(2.0005)-d(1.9995)}{2.0005-1.9995}

we get that:

d(1.9995)=\frac{(1.9995)^{3}}{6}+4(1.9995)=9.33033358

d(2.0005)=\frac{(2.0005)^{3}}{6}+4(2.0005)=9.33633358

so:

V_{average}=\frac{9.33633358-9.33033358}{2.0005-1.9995}=6.00000004m/s

(d) [2, 2.00001]

V_{average}=\frac{d(2.00001)-d(2)}{2.00001-2}

we get that:

d(2)=\frac{(2)^{3}}{6}+4(2)=9.33333333

d(2.00001)=\frac{(2.00001)^{3}}{6}+4(2.00001)=9.33339333

so:

V_{average}=\frac{9.33339333-9.33333333}{2.00001-2}=6.00001m/s

Since the closer the interval is to 2 the more it approaches to 6m/s, then the instantaneous velocity of the athlete at t=2s is 6m/s

8 0
3 years ago
Helppppp please I will give brainliest​
ExtremeBDS [4]

Answer:

0

Step-by-step explanation:

Y-intercept is where the line touches the y-axis, in this case it was the origin (0,0) so the y-intercept is 0

4 0
3 years ago
Is (-2, -6) a solution to this system of equations? 3x + 18y = -14 15x − 7y = 12 yes no
soldi70 [24.7K]

Answer:

No

Step-by-step explanation:

Plug in (-2, -6) to see if it's the solution or not

3(-2) + 18(-6) ?  -14

-6  + ( -108) ? -14

-114 ≠ -14

Answer is NO

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4 years ago
Adding polynomial expressions
slamgirl [31]

Answer:Start with: 1.2x2 + 6x + 5 + 3x2 − 2x − 1.

2.Place like terms together:2x2+3x2 + 6x−2x + 5−1.

3.Which is:(2+3)x2 + (6−2)x + (5−1)

4.Add the like terms:5x2 + 4x + 4.

Step-by-step explanation:

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4 years ago
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Nat2105 [25]

Answer:

flips, reflection y rotation

Step-by-step explanation:

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3 years ago
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