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hichkok12 [17]
2 years ago
11

Brady has a bag with 6 black pens, 6 blue pens, and 2 red pens. If he grabs a pen at random, what is the probability that the pe

n is not red?.
Mathematics
1 answer:
DedPeter [7]2 years ago
8 0

Answer: 6/7

Step-by-step explanation:

If the pen is not red, it must be either black or blue.

Therefore, the probablity is (6+6)/(6+6+2)

= 12/14

= 6/7

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20 Is 80 percent of what number?<br> A 21<br> В 22<br> С 24<br> D 25
gogolik [260]

Answer:

D. 25

Step-by-step explanation:

If this helps, please mark this as brainliest

6 0
3 years ago
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Find the area of the shaded portion in the square. Show all work for full credit.
kumpel [21]
Well, what I would do [not sure if it's the correct way], is use the white area as a sector of a circle. The top right of the box is the center of the circle, so the radius is 6.
Then, by the white portion being one quarter of the circle (90° out of 360°), I could calculate the that pink shaded region = the total square (6×6) minus the white sector.
So area (A) of white sector (s): A(s) = 1/4×pi×r^2
A(s) =  \frac{\pi {r}^{2} }{4}  =  \frac{\pi  \times {6}^{2} }{4}  \\ A(s) =  \frac{36\pi}{4}  = \frac{9\pi}{1}  = 9x3.142 \\ A(s) = 28.27
36 - 28.27 = 7.73
6 0
3 years ago
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Two of them are drawn simultaneously from a deck of 48 cards.
Elina [12.6K]

The required probability is
a) both are cups is 0.05

b) At least one cup is 0.19

c) One is a cup and the other is a sword is   0.06

<h3 /><h3>What is probability?</h3>

Probability can be defined as the ratio of favorable outcomes to the total number of events.

a) for both are cups

P= 12*11/48*47
p = 0.05

b) for  At least one cup
p = 12*36/48*47
p = 0.19

c) for One is a cup and the other is a sword
p = 12*12/48*47
p = 0.06

Thus, the required probability is 0.05, 0.19, 0.06

Learn more about probability here:

brainly.com/question/14290572

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6 0
2 years ago
Which system of inequalities has a solution set that is a line?
Korolek [52]

We're going to solve each of the systems to determine the solution.

<u>System 1</u>

x+y \geq  3\\ x+y \leq  3

using a graph tool

the solution is the line x+y=3

see the attached figure N 1

<u>System 2</u>

x+y \geq  -3\\ x+y \leq  3

using a graph tool

the solution is the shaded area

see the attached figure N 2

<u>System 3</u>

x+y >  3\\ x+y <  3

using a graph tool

The system has no solution

see the attached figure N 3

<u>System 4</u>

x+y >  -3\\ x+y <  3

using a graph tool

the solution is the shaded area

see the attached figure N 4

therefore

<u>the answer is</u>

<u>System 1</u>

x+y \geq  3\\ x+y \leq  3



7 0
3 years ago
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Weekly demand for milk at a small grocery store is normally distributed with a mean of 251 gallons per week and standard deviati
slavikrds [6]

Solution

Given

mean = 251

standard deviation = 33

(a)

\begin{gathered} P(Z

Hence, X = 300

7 0
1 year ago
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