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katrin [286]
2 years ago
8

What is the value of x? enter your answer in the box. x =

Mathematics
2 answers:
SVEN [57.7K]2 years ago
5 0
The answer is x=54. You would set up your answer as 2x + 2= 3x -52. Then move 2x over to line up with 3x. 3x-2x= x. Next you would add 52 with 2 to get 54 as your answer! Hope this helped :)
MaRussiya [10]2 years ago
3 0

Answer:

<u>x = 54</u>

Step-by-step explanation:

These are vertically opposite angles, meaning their angle measures are equal.

2x + 2 = 3x - 52

<u>x = 54</u>

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All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be
Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

A = a + (A \cap B)

In which a is the probability that a student is proficient in reading but not mathematics and A \cap B is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

B = b + (A \cap B)

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

(A \cup B) + C = 1

In which

(A \cup B) = a + b + (A \cap B)

65% were found to be proficient in both reading and mathematics.

This means that A \cap B = 0.65

78% were found to be proficient in mathematics

This means that B = 0.78

B = b + (A \cap B)

0.78 = b + 0.65

b = 0.13

85% of the students were found to be proficient in reading

This means that A = 0.85

A = a + (A \cap B)

0.85 = a + 0.65

a = 0.20

Proficient in at least one:

(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98

What is the probability that the student is proficient in neither reading nor mathematics?

(A \cup B) + C = 1

C = 1 - (A \cup B) = 1 - 0.98 = 0.02

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0
2 years ago
Help me plz, thanks.
chubhunter [2.5K]
6/20 chance or simplified would be 3/10. Answer [D] is correct.
5 0
3 years ago
Read 2 more answers
Please help with this
solong [7]
Could you retake the picture it’s hard to read
3 0
2 years ago
The triangles shown below must be congruent. right awnsers only please.
tankabanditka [31]
It is true. The triangles are congruent.
8 0
3 years ago
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PLZ HELP 30points and brainlist
MariettaO [177]
The answer is b so good luck and i hope that helps
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3 years ago
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