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3 years ago

Anyone know the solution for this equation

Mathematics

1 answer:

ohaa [14]3 years ago

3 0

Answer:

Step-by-step explanation:

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PLS HELP PLS PLS PLS WILL MARK BRAINLIEST

Ksenya-84 [330]

Answer: C
It’s going down by the same rate of change, 2.

4 0

3 years ago

Evaluate the expression<br> cos(30°)=

alina1380 [7]

Answer:

$cos (30) =\sqrt{\frac{3}{2} } =0.8660$

Step-by-step explanation:

By using the cos square identity in trigonometry i.e., cos2ϴ = 1 – sin2 ϴ, we can evaluate the exact value of cos(33 ). For calculating the exact value of cos(∏/6), we have to substitute the value of sin(30°) in the same formula.

cos(30°) = √1 – sin230°

The value of sin30° is 1/2 (Trigonometric Ratios)

cos(30°) = √1 – (1/2)2

cos(30°) = √1 – (1/4)

cos(30°) = √(1 * 4 – 1)/4

cos(30°) = √(4 – 1)/4

cos(30°) = √3/4

Therefore, cos(30°) = √3/2

3 0

2 years ago

Read 2 more answers

Please help me! I have no idea how to do this

elena-s [515]

The best way to do this is to make up values for the sides.

Say the lengths of square B's sides are each 4 cm. That means A's sides are 2 cm.

So, the area of square B is 4^2 = 16 cm^2, and A's area is 4 cm^2. We can see the shaded area is half of A, so it's 2 cm^2.

What percent of 16 is 2?

2 / 16 * 100 = 12.5%

5 0

3 years ago

How do you estimate 403,446 +396,755

Bingel [31]

403446 is around 400000 so you round that up in your head. 396755 is close to 400000 so you round that up in your head to. Then you add them together to get 800000, which you can do in your head.

6 0

3 years ago

Read 2 more answers

A 2?-ft wide circular track for a camera dolly is set up for a movie scene. The two rails of the track form concentric circles.

navik [9.2K]

Answer: A wheel on the outer rail travel 12.57 ft more than a wheel on the inner rail of the track.

Step-by-step explanation:

Since we have given that

Radius of inner circle = 57 ft

As we know the formula for "Circumference of circle":

$Distance=Circumference=2\pi r\\\\Distance=2\times \frac{22}{7}\times 57\\\\Distance=358.28\ Ft$

Since we have also mentioned that there is 2 feet wide circular track for a camera dolly.

So, Radius of outer circle will be given as

$57+2\\=59\ ft$

So, Distance = Circumference is given by

$Distance=2\pi R\\\\Distance=2\times \frac{22}{7}\times 59\\\\Distance=370.85\ ft$

Hence, Difference between the outer rail travel than a wheel on the inner rail travel is given by

$370.85-358.28\\\\=12.57\ ft$

Therefore, A wheel on the outer rail travel 12.57 ft more than a wheel on the inner rail of the track.

7 0

3 years ago