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Fiesta28 [93]
3 years ago
15

The rate of change of the volume of a snowball that is melting is proportional to the surface area of the snowball. Suppose the

snowball is perfectly spherical. Then the volume (in centimeters cubed) of a ball of radius r centimeters is 4/3πr3. The surface area is 4πr2. Set up the differential equation for how r is changing. Then, suppose that at time t = 0 minutes, the radius is 10 centimeters. After 5 minutes, the radius is 8 centimeters. At what time t will the snowball be completely melted?
Mathematics
1 answer:
Ostrovityanka [42]3 years ago
4 0

Answer:

The time will be 25 minutes in which snowball be completely melted.

Step-by-step explanation:

Given : The rate of change of the volume of a snowball that is melting is proportional to the surface area of the snowball. Suppose the snowball is perfectly spherical.

Then the volume (in centimeters cubed) of a ball of radius r centimeters is V=\frac{4}{3}\pi r^3

The surface area is S=4\pi r^2

Set up the differential equation for how r is changing. Then, suppose that at time t = 0 minutes, the radius is 10 centimeters. After 5 minutes, the radius is 8 centimeters.

To find : At what time t will the snowball be completely melted?

Solution :

Using given condition,

\frac{dV}{dt}\propto S

\frac{dV}{dt}=\lambda S ....(1)

V=\frac{4}{3}\pi r^3

\frac{dV}{dt}=\frac{4}{3}\pi 3r^2\frac{dr}{dt}

Substitute in (1),

\frac{4}{3}\pi 3r^2\frac{dr}{dt}=\lambda 4\pi r^2

\frac{dr}{dt}=\lambda

r=\lambda t+c

Now, t=0 , r=10

So, 10=\lambda(0)+c

c=10

i.e. r=\lambda t+10

After 5 minutes, t=5 , r=8

8=\lambda (5)+10

5\lambda=-2

\lambda=-\frac{2}{5}

The equation form is r=-\frac{2}{5}t+10

The snowball be completely melted means radius became zero.

0=-\frac{2}{5}t+10

\frac{2}{5}t=10

t=\frac{10\times 5}{2}

t=25

The time will be 25 minutes in which snowball be completely melted.

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