Question

400.0 ml of a gas are under pressure of 80.0 kpa what would the volume of the gas be at a pressure of 100.0 kpa

Answer 1

Answer:

The final volume is 320 mL at pressure of 100 kPa.

Step-by-step explanation:

Boyle's law gives the relation between volume and pressure of a gas. It states that at constant temperature, volume is inversely proportional to its pressure such that,

$V\propto \dfrac{1}{P}\\\\P_1V_1=P_2V_2$

Let

$V_1=40\ mL\\\\P_1=80\ kPa\\\\P_2=100\ kPa$

We need to find $V_2$. Using above equation, we get :

$V_2=\dfrac{P_1V_1}{P_2}\\\\V_2=\dfrac{400\times 80\times 10^3}{100\times 10^3}\\\\V_2=320\ mL$

So, the final volume is 320 mL at pressure of 100 kPa.