All categories

2 years ago

PLEASE HELP!!

Mathematics

2 answers:

QveST [7]2 years ago

8 0

Answer is D and E

Step-by-step explanation:

Option D u will multiply each side by the LCM which is 3 and u will get the answer to be C=9

option E u will divide both side by 4 and u will get the answer to be C=9

Yuri [45]2 years ago

4 0

Answer: d and e

Step-by-step explanation:

a) 4 - 9 = 5 FALSE

b) 20 = 14 + 9 FALSE

c) 15 = 9 - 6 FALSE

d) 9 divided by 3 = 3 TRUE

e) 36 = 4 x 9 TRUE

You might be interested in

Use the formula P=21+2w to find the width of a rectangle when the length is 18cm and perimeter is 48 ..

KIM [24]

Answer:

w=6

Step-by-step explanation:

P=2(L)+2(w)

48= 2(18)+2w

48=36+2w

12=2w

w=6

checking;

48= 2(18)+2(6)

48= 36+12

48= 48

8 0

3 years ago

12x-13x write an equivalent expression.

harina [27]

Answer:

-x

Step-by-step explanation:

12x-13x is -1x which can also be written as -x

5 0

2 years ago

Example of a number thats not rational and tell me why its not

Mekhanik [1.2K]

One irrational number is π, also known as pi. A rational number is one that can be written as a ratio of two integers (whole numbers). Pi goes on forever, so it can't be written as a ratio. Therefore, π is irrational.

6 0

3 years ago

Read 2 more answers

PLEASE HURRY!! TIMED!! WILL GIVE BRAINLIEST!!!

tensa zangetsu [6.8K]

Answer:

2/3 +9.26 = 0.6666+9.26=rational

4 0

2 years ago

It is estimated that 0.54 percent of the callers to the Customer Service department of Dell Inc. will receive a busy signal. Wha

stira [4]

Using the binomial distribution, it is found that there is a 0.8295 = 82.95% probability that at least 5 received a busy signal.

<h3>What is the binomial distribution formula?</h3>

The formula is:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem:

0.54% of the calls receive a busy signal, hence p = 0.0054.

A sample of 1300 callers is taken, hence n = 1300.

The probability that at least 5 received a busy signal is given by:

$P(X \geq 5) = 1 - P(X < 5)$

In which:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4).

Then:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{1300,0}.(0.0054)^{0}.(0.9946)^{1300} = 0.0009$

$P(X = 1) = C_{1300,1}.(0.0054)^{1}.(0.9946)^{1299} = 0.0062$

$P(X = 2) = C_{1300,2}.(0.0054)^{2}.(0.9946)^{1298} = 0.0218$

$P(X = 3) = C_{1300,3}.(0.0054)^{3}.(0.9946)^{1297} = 0.0513$

$P(X = 4) = C_{1300,4}.(0.0054)^{4}.(0.9946)^{1296} = 0.0903$

Then:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0009 + 0.0062 + 0.0218 + 0.0513 + 0.0903 = 0.1705.

$P(X \geq 5) = 1 - P(X < 5) = 1 - 0.1705 = 0.8295$

0.8295 = 82.95% probability that at least 5 received a busy signal.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

6 0

1 year ago