The average height of the fence is 2 m; its length is 20π m. So, its 2-sided area is
A = 2*(2 m)*(20π m) = 80π m² ≈ 251 m²
At 1 L/(100 m²), it will take 2.51 L of paint to paint both sides.
3.3333333333..... is the answer
Answer:
x = 165°
Step-by-step explanation:
x° = 360 - (the measure of one interior angle of the octagon + the measure of one interior angle of the equilateral ∆)
Each interior angle of a regular octagon = 135° ([tex] \frac{(n - 2)180}{n} = 135°)
An equilateral ∆ has equal angles, each measuring 60°.
Therefore:
x° = 360° - (135° + 60°)
x = 360 - 195
x = 165°
Assuming no border or waste, 9m by 16 m translates to 29.52' x 52.49'.
use 32/8=4 sheets of plywood to cover the width on the 8' side.
For the length, use 52/4=13 pieces on the 4' side.
This gives a total of 4*13=52 sheets.
The extra 0.49' x 29.52 can be covered using the extra from the last four sheets for the width.
Check:
Area to be covered: 29.52*52.49=1550 sq. ft.
Area of plywood supplied = 52*4'x8'= 1664 sq. ft, > 1550 sq.ft.
