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liubo4ka [24]
2 years ago
12

A rental car company charges $68.64 per day to rent a car and $0.12 for every mile driven Jackson wants to rent a car knowing th

at he plans to drive 500 miles he has at most $210 to spend what is the maximum amount of number of days that Jackson can rent a car while staying with his budget
Mathematics
2 answers:
adell [148]2 years ago
8 0

Answer:

maximum amount of number of days that Jackson can rent a car while staying with his budget is 2 days

Step-by-step explanation:

first of all find the amount of money he will spend for 500 miles

in this case we multiply 0.12 by 500

=> 0.12 × 500

=> 60

subtract 60 from the money budgeted which is $210

=> $210 - 60

=> 150

divide 150 by the company charges per day which is dollars 68.64

=> 150 ÷ 68.64

divide 150 by 68.64

=> 2.185314685314685

approximately

=> 2 days

Rzqust [24]2 years ago
8 0

Answer:

2

Step-by-step explanation:

  • Let's say the number of days that Jackson can rent the car is x.
  • By the question to know
  • 6
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Part (i)

I'm going to use the notation T(n) instead of T_n

To find the first term, we plug in n = 1

T(n) = 2 - 3n

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Repeat for n = 2 to find the second term

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<h3>Answers: -1, -4</h3>

==============================================

Part (ii)

Plug in T(n) = -61 and solve for n

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n = -63/(-3)

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Note that plugging in n = 21 leads to T(21) = -61, similar to how we computed the items back in part (i).

<h3>Answer:  21st term</h3>

===============================================

Part (iii)

We're given that T(n) = 2 - 3n

Let's compute T(2n). We do so by replacing every copy of n with 2n like so

T(n) = 2 - 3n

T(2n) = 2 - 3(2n)

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Now subtract T(2n) from T(n)

T(n) - T(2n) = (2-3n) - (2-6n)

T(n) - T(2n) = 2-3n - 2+6n

T(n) - T(2n) = 3n

Then set this equal to 24 and solve for n

T(n) - T(2n) = 24

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n = 24/3

n = 8

This means 2n = 2*8 = 16. So subtracting T(8) - T(16) will get us 24.

<h3>Answer: 8</h3>
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