The mean is where you add all of the numbers in that set together, and divide it by the amount of numbers you have. E.g. For Set 1 - 10 + 15 + 20 + 25 + 30 + 50 = 150 ÷ 6 = 25
For Set 2 you just repeat the process:
1. Add the numbers in the set together, this gives you a total of 111
2. Then divide 111 by 5 as you have 5 numbers, giving you 22.2
Therefore set 1 has the higher mean :)
The answer is C, set 1, 25 :)
Answer:
After 2009 the quality of the forests in this country improving.
Step-by-step explanation:
Consider the provided function.
Substitute f'(t)=0.
It is given that (0 ≤ t ≤ 10)
The test interval are (0,5) and (5,10)
For (0 < t < 5) the value of 
For (5 < t < 10) the value of 
Hence, the function is increasing from (5,10).
t = 0 corresponds to 2004.
Therefore, after 2009 the quality of the forests in this country improving.
Answer:
2500÷$3.21 =778.81
just round to the nearest whole number
Answer:
see explanation below
Step-by-step explanation:
You have three pairs of shoes (white, brown, and black), and you have 6 pairs of pants ( brown, blue, grey, white, sand, and black)
We use the Fundamental Counting Principle to find the number of possible pant-shoe combinations:
3 * 6 = 18
then we can find the probability of wearing by random selection brown shoes with either blue or grey pants:
prob (brown shoes & blue pants) + prob (brown shoes & grey pants) =
= 1/18 + 1/18 = 2/18 = 1/9
Since f(x) is (strictly) increasing, we know that it is one-to-one and has an inverse f^(-1)(x). Then we can apply the inverse function theorem. Suppose f(a) = b and a = f^(-1)(b). By definition of inverse function, we have
f^(-1)(f(x)) = x
Differentiating with the chain rule gives
(f^(-1))'(f(x)) f'(x) = 1
so that
(f^(-1))'(f(x)) = 1/f'(x)
Let x = a; then
(f^(-1))'(f(a)) = 1/f'(a)
(f^(-1))'(b) = 1/f'(a)
In particular, we take a = 2 and b = 7; then
(f^(-1))'(7) = 1/f'(2) = 1/5
