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tamaranim1 [39]

1 year ago

14

What is the value of m in the equation 5m − 7 = 6m 11? 18 1 −18 −1.

1 answer:

denpristay [2]1 year ago

6 0

Answer:

-7 = m

Step-by-step explanation:

5m − 7 = 6m

Subtract 5m from each side

5m-5m − 7 = 6m-5m

-7 = m

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Problem Emily convinced her mom to buy a giant box of her favorite cereal. Her mom doesn't think the box will fit on their shelf

Doss [256]

The height of the box should be 40cm

3 0

2 years ago

Find the formula for an exponential function that passes through the two points give.

Ksenya-84 [330]

Answer:

$y=3(2)^{x}$

Step-by-step explanation:

Given.

Two points are given.

$(x, y)=(-1,\frac{3}{2})$ and $(x, y)=(3,24)$

An exponential function is in the general form.

$y=a(b)^{x}$ -------(1)

We know the points $(-1,\frac{3}{2})$ and $(3,24)$

put the first point value in equation 1

$\frac{3}{2}=a(b)^{-1}$

$\frac{3}{2}=\frac{a}{b}$

$a=\frac{3}{2}\times b$ --------(2)

put the second point value in equation 1

$24=a(b)^{3}$ ----------(3)

Put the a value from equation 2 to equation 3

$24=\frac{3}{2}\times b(b)^{3}$

$b^{3+1}=\frac{24\times 2}{3}$

$b^{4} = 16\\b=\sqrt[4]{16} \\b=2$

Put the b value in equation 2

$a=\frac{3}{2}\times 2$

$a=3$

Put the a and b value in equation 1

$y=3(2)^{x}$

So, the exponential function that passes through the points $(-1,\frac{3}{2})$ and $(3,24))$ are $y=3(2)^{x}$ .

6 0

2 years ago

Create an equivalent ratio to 10:16 by dividing both sides by 2. What is the equivalent ratio?

Darya [45]

10 / 2 = 5

16 / 2 = 8

The equivalent ratio is 5:8

5 0

2 years ago

Solve for x. x2 + x - 6 = 0 A. -2, -3 B. -2, 3 C. 2, -3 D. 2, 3

stiv31 [10]

Factor x^2 + x - 6

(x - 2)(x + 3) = 0

Solve for x

Ask yourself; When will (x - 2)(x + 3) equal zero?

When x - 2 = 0 or x + 3 = 0

Then solve for each of the two equations above

<em>x = 2, -3</em>

<u>Answer: C. 2, -3</u>

5 0

3 years ago

Read 2 more answers

A+2/a-5÷a+1/a2-8a+15

krok68 [10]

For $A+\frac{2}{a}-\frac{5}{a}+\frac{1}{a^2}-8a+15$

Combine the fractions $\frac{2}{a} - \frac{5}{a} \ \textgreater \ \mathrm{Apply\:rule}\:\frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c} \ \textgreater \ \frac{2-5}{a}$

$\mathrm{Subtract\:the\:numbers:}\:2-5=-3 \ \textgreater \ \frac{-3}{a}$

$\mathrm{Apply\:the\:fraction\:rule}:\ \frac{-a}{b}=-\frac{a}{b} \ \textgreater \ -\frac{3}{a}$

Therefore our final answer is $A-\frac{3}{a}+\frac{1}{a^2}-8a+15$

Hope this helps!

3 0

2 years ago