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Over [174]
3 years ago
7

How many pounds does 6.5 dozen cupcakes weigh? • 1 cupcake = 35.3 grams

Mathematics
1 answer:
melisa1 [442]3 years ago
6 0

Answer:

35.3g * 78 =2,753.4g

2,753.4g = 6.07lbs

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Answer:

B. Dan walked uphill, then downhill.

Step-by-step explanation:

The place that the slope went up is based on the distance from the starting point, so the distance is up then down. I hope this helped and please mark me as brainliest!

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A graph is shown below:
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The answer would be C because b=+16 which means that it intercepts line y at 16, which is shown in the graph.
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If you sold 17 units this week out of 153 units in inventory, what percent of your inventory did you sell?
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11.1%

Step-by-step explanation:

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3 years ago
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There are two college entrance exams that are often taken by students, Exam A and Exam B. The composite score on Exam A is appro
elena55 [62]

Answer:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Two exams. The exam that you did score better is the one in which you had a higher zscore.

The composite score on Exam A is approximately normally distributed with mean 20.1 and standard deviation 5.1.

This means that \mu = 20.1, \sigma = 5.1.

You scored 24 on Exam A. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{24 - 20.1}{5.1}

Z = 0.76

The composite score on Exam B is approximately normally distributed with mean 1031 and standard deviation 215.

This means that \mu = 1031, \sigma = 215.

You scored 1167 on Exam B, s:

Z = \frac{X - \mu}{\sigma}

Z = \frac{1167 - 1031}{215}

Z = 0.632

You had a better Z-score on exam A, so you did better on that exam.

The correct answer is:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

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3 years ago
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