Question

Polygon ABCD is translated to create polygon A′B′C′D′. Point A is located at (1, 5), and point A′ is located at (-2, 1). What is the distance from B to B′ ?

Answer 1

Translated
so the distance from A to A' should be the same as form B to B'

distance formula
distance between (x1,y1) and (x2,y2) is
$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

so distance between (1,5) and (-2,1) is
$D=\sqrt{(-2-1)^2+(1-5)^2}$
$D=\sqrt{(-3)^2+(-4)^2}$
$D=\sqrt{9+16}$
$D=\sqrt{25}$
$D=5$

the distance is 5 units

Answer 2

Answer:

5 units

Step-by-step explanation: