3 years ago

Algebra 2 question! Can someone please help me with this?

Mathematics

1 answer:

NARA [144]3 years ago

8 0

Answer:

Step-by-step explanation:

since OP = XP not necessary true

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Let f(x) = 6x2 + 5 and g(x) = 3x - 5. Find f(g(0)).

professor190 [17]

First you do g(0):
g(0) = 3(0) -5
g(0) = -5
then you do f(-5):
f(-5) = 6(-5)2 +5

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3 years ago

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Step-by-step explanation:

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3 years ago

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3 years ago

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3 years ago

Point E is located at (−1, 6) and point F is located at (3, 9)

Mars2501 [29]

Answer:

$(x,y)=(\frac{7}{5},\frac{39}{5})$

Step-by-step explanation:

We have given:

E is (-1,6) and F is (3,9)

And ratios are 3:2

We will use the section formula to find the required coordinates:

section formula= $(\frac{m_1x_2+m_2x_1}{m_1+m_2},\frac{m_1y_2+m_2y_1}{m_1+m_2})$

Here, $m_1=3,m_2=2,x_1=-1,x_2=3,y_1=6,y_2=9$

On substituting the values in the formula we get:

$(x,y)=(\frac{3\cdot 3+2\cdot (-1)}{3+2},\frac{3\cdot 9+2\cdot 6}{3+2})$

$\Rightarrow (x,y)=(\frac{9-2}{5},\frac{27+12}{5}$

$\Rightarrow (x,y)=(\frac{7}{5},\frac{39}{5})$

Hence, required coordinates are: $(x,y)=(\frac{7}{5},\frac{39}{5})$

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4 years ago