The answer is 1/3.
To get to this conclusion you must halve both the numerator and the denominator until you reach a point where each number can no longer be halved.
32/96
16/48
8/24
4/12
2/6
1/3
we know that
A <u>geometric sequence</u> is a sequence of numbers in which the ratio between consecutive terms is constant
so
Let







therefore
The common ratio is equal to 
<u>the answer is</u>
The common ratio is 1.02
Answer:
3 figures
Step-by-step explanation:
Just follow these steps!
Non-zero digits are always significant.
Any zeros between two significant digits are significant.
A final zero or trailing zeros in the decimal portion ONLY are significant.
Answer:
6x - 4
Step-by-step explanation:
The problem is asking for 4 less than a number times 6. Set this number equal to x, leaving us with 4 less than 6x, or 6x - 4.
Answer:
the cost of increase is $5.00