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2 years ago

Simplify 4.2^2 x 5.1^2 x 4.2^4 x 5.1^3

Mathematics

2 answers:

mario62 [17]2 years ago

8 0

Answer:

=18938545.55220... x^3

Step-by-step explanation:

ivann1987 [24]2 years ago

6 0

Answer: 18938545.55220567

Step-by-step explanation:

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A radio station is having a promotion in which every 12th caller receives a free concert ticket and every 15th caller receives a

marusya05 [52]

For this, we need to find the lowest common multiple of 12 and 15....

common multiples of 12 : 12,24,36,48,60
common multiples of 15 : 15,30,45,60
LCM = 60

the caller that will be the first to win both is the 60th caller

7 0

3 years ago

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Which facts are true for the graph of the function below? Check all that apply.

AlekseyPX

B. the x-intercept is (1,0).

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3 years ago

Prove the following identity. [sin(x+y)+sin(x-y)]/[cos(x+y)+cos(x-y)] = tan(x)

tia_tia [17]

$\frac{sin(x + y) + sin(x - y)}{cos(x + y) + cos(x - y)} = tan(x)$
$\frac{(sin(x)cos(y) + cos(x)sin(y)) + (sin(x)cos(y) - cos(x)sin(y))}{(cos(x)cos(y) - sin(x)sin(y)) + (cos(x)cos(y) + sin(x)sin(y))} = tan(x)$
$\frac{(sin(x)cos(y) + sin(x)cos(y)) + (cos(x)sin(y) - cos(x)sin(y))}{(cos(x)cos(y) + cos(x)cos(y)) + (-sin(x)sin(y) + (sin(x)sin(y))} = tan(x)$
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4 0

3 years ago

If $1= rs 115.4 ( buying rate ) and $1=rs116.20(selling rate). find the profit while selling and buying $6000.

Galina-37 [17]

The profit is Rs.4800.

<h3>What is profit?</h3>

When, in a transaction, the selling price is greater than the cost price, it means we earn a profit. It is calculated with the help of the formula: Profit = Selling price - Cost price.

Given that,

S.P =$6000

C.P = $6000

If, 1$ = Rs.115.4 (in cost price)

1$ = Rs.116.20 (in selling price)

Then,

C.P = Rs. 115.40×6000

S.P = Rs. 116.20×6000

Then,

Profit = S.P-C.P

= 116.20×6000 -115.40×6000

= (116.20-115.40)×6000

= 0.80×6000

= Rs.4800

Hence, The profit is Rs.4800.

To learn more about profit from the given link:

brainly.com/question/19104371

#SPJ4

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2 years ago

Question below

Ksivusya [100]

Answer:

$m \times H=\left[\begin{array}{c c c}\boxed{-9} & \boxed{36} & \boxed{-\dfrac{9}{2}}\end{array}\right]$

Step-by-step explanation:

Calculate the value of m

Given:

$3\left[\begin{array}{c c}-1 & 2 \\4 & 8\end{array}\right]=\dfrac{2}{3}m \times \left[\begin{array}{c c}-1 & 2 \\4 & 8\end{array}\right]$

Therefore:

$\implies 3=\dfrac{2}{3}m$

$\implies m=3 \times \dfrac{3}{2}$

$\implies m=\dfrac{9}{2}$

Calculate the value of H

Given:

$\left(H+ \left[\begin{array}{c c c}1 & 4 & -2\end{array}\right]\right)+\left[\begin{array}{c c c}3 & 2 & -6\end{array}\right]=\left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]+\left(\left[\begin{array}{c c c}1 & 4 & -2\end{array}\right]+\left[\begin{array}{c c c}3 & 2 & -6\end{array}\right]\right)$

Therefore:

$\implies H= \left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]$

Calculating m × H

$\implies m \times H=\dfrac{9}{2} \times \left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]$

$\implies m \times H=\left[\begin{array}{c c c}\dfrac{9}{2}(-2) & \dfrac{9}{2}(8) & \dfrac{9}{2}(-1)\end{array}\right]$

$\implies m \times H=\left[\begin{array}{c c c}-9 & 36 & -\dfrac{9}{2}\end{array}\right]$

7 0

2 years ago