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Tatiana [17]
3 years ago
6

I help on these problems

Mathematics
1 answer:
Flura [38]3 years ago
6 0
Which number is 1,000 less than 24,819 do 24,819-1000=23,819

Which number is 1,000 greater than 28,283 do 28,283+1,000=29,283 Answer choice B
The other questions are un readable
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The difference between Sheila and Robbie's ages is 12. The sum of their ages is 42. If Sheila is the younger of the two, how old
Colt1911 [192]
Let's say that Robbie's age is represented by r and Sheila's age is represented by s. Since we know that r is greater than s, we can set up a difference equation of r - s = 12. We also know that r + s = 42. Now, we can simply add the two equations and get that 2r = 54, then finally that r = 54. Therefore, Robbie is 54 years old.

Hope this helps!
6 0
3 years ago
Read 2 more answers
Two rectangular pyramids are similar. The smaller pyramid has a volume of 12 cubic feet, and
ivolga24 [154]

Volume of Big Pyramid= 324 cubic feet

Volume of small pyramid= 12

Volume of a pyramid is given as V=⅓xBasexheight

For the big pyramid

324=⅓xbasexheight

But 324= 27x12

Then for the big pyramid,

12=1/3x1/27xbasexheight

For the small pyramid

12=1/3xbasex6

Since both base are similar and from the equations derived so far

1/3x1/27xheight=1/3x6

Height=27x3x1/3x6=162feet

7 0
4 years ago
Math - Finding Volume - Answer All if you can
elena55 [62]
A) 296
B)348
C)828

Plz mark brainliest
5 0
3 years ago
Expand: (2n + 5k)2 polynomial identeties
Tanzania [10]
(2n + 5k)^2 = (2n + 5k)(2n + 5k)
Here we need to use FOIL
First - 2n * 2n = 4n^2
Outside - 2n * 5k = 10nk
Inside - 5k * 2n = 10nk
Last - 5k * 5k = 25k^2

That gives us 4n^2 + 10nk + 10nk + 25k^2, we can combine 10nk + 10nk to give 20nk, and a final equaion of 4n^2 + 20nk + 25k^2
4 0
4 years ago
Read 2 more answers
___cosb=1/2[sin(a+b) + sin(a-b)
Bond [772]
Use the addition and subtraction theorem:

sin (A + B) = sin A + cos B
sin (A - B) = sin A - cos B

From there it's just a matter of simplification.

sin A cos B = 1/2 [ sin (A + B) + sin (A - B) ]
sin A cos B = 1/2 [ sin A cos B + cos A sin B + sin (A - B) ]
sin A cos B = 1/2 [ sin A cos B + cos A sin B + sin A cos B - cos A sin B ]
sin A cos B = 1/2 [ 2 sin A cos B ]
sin A cos B = sin A cos B
7 0
3 years ago
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